如何替换完全匹配或部分匹配的完整单词

Question

我正在尝试使用 preg_replace 或 str_ireplace 来包装跨度 class 标记找到的关键字，但是使用 str_ireplace 它将把 'wooding' 等单词切成两半，例如：

<span class="highlight">wood</span>ing

这是一个针、大海捞针和必需品的例子return:

针数：

wood

干草堆：

wood and stuff
this doesnt contain the keyword
Wooding is what we do

我想要什么 returned:

<span class="highlight">wood</span> and stuff
this doesnt contain the keyword
<span class="highlight">Wooding</span> is what we do

这是我的 preg_replace 实验的 link： http://www.phpliveregex.com/p/i4m

Answer 1

您需要在结束词边界之前使用带有可选字符的正则表达式和词边界，以确保它正是您要查找的词。尝试：

$string = 'wood and stuff
this doesnt contain the keyword
Wooding is what we do';
echo preg_replace('/\b(wood[a-z]*)\b/i', '<span class="highlight"></span>', $string);

PHP 演示：https://eval.in/689239
正则表达式演示：https://regex101.com/r/f9B6mL/1

对于多个术语，您可以使用非捕获组和 | 进行术语分隔。

$string = 'wood and metal stuff
this doesnt contain the keyword
Wooding is what we do metals';
echo preg_replace('/\b((?:wood|metal)[a-z]*)\b/i', '<span class="highlight"></span>', $string);

演示：https://eval.in/689256

Answer 2

试试这个正则表达式：\b(wood.*?)\b，它匹配以 wood 开头后跟任意数量的单词字符的单词。

$intput = 'put your input here';
$result = preg_replace(/\b(wood.*?)\b/i, '<span class="highlight">\1</span>', $input);

Answer 3

怎么样：

$str = <<<EOD
wood and stuff
this doesnt contain the keyword
Wooding is what we do
EOD;
$needle = 'wood';
$str = preg_replace("/\w*$needle\w*/is", '<span class="highlight">[=10=]</span>', $str);
echo $str,"\n";

输出：

<span class="highlight">wood</span> and stuff
this doesnt contain the keyword
<span class="highlight">Wooding</span> is what we do

如何替换完全匹配或部分匹配的完整单词

How to replace full words that are either fully or part matched

php

regex

preg-replace

str-replace