c中的哨兵循环执行

Question

我有以下代码，我希望它在只输入一次哨兵号码后中断，但目前我必须输入两次哨兵号码才能中断代码。有什么想法吗？

#include <stdio.h>// Include a standard C Library
#define Sentinel_Numb -1
int main(){

  int ID[360];              
  float seconds[360];
  int i = 0;

 printf("please enter the  ID and how many seconds to calculate enter  -1 when done\n");

while (1)                           
{
    scanf_s("%d",&ID[i]);
    scanf_s("%f",&seconds[i]);

    if( ID[i] == Sentinel_Numb || seconds[i] == Sentinel_Numb){
       break;
         }
    i++;
}

return 0;
}

Answer 1

更改为：

scanf_s("%d",&ID[i]);
if (ID[i] == Sentinel_Numb)
    break;
scanf_s("%f",&seconds[i]);
if (seconds[i] == Sentinel_Numb)
    break;

Answer 2

while (1)                           
{
    scanf_s("%d",&ID[i]);

    if (ID[i] == Sentinel_Numb)
        break; 

    scanf_s("%f", &seconds[i]);

    if (seconds[i] == Sentinel_Numb)
        break;
    i++;
}

c中的哨兵循环执行

sentinel loop execution in c

c

loops

sentinel