UI 线程问题的竞争条件。

Question

这是我正在处理的代码。在这里我无法更新 UI 直到我的 OnResponse 是 finished.Because 我们正在做 doInBackgrnd，所以我的 textresponse 是空的。因为 onPostExecute 紧随其后。

对于他，我认为 PublicProgres 应该有所帮助。 如何在AsyncTask调用PublishProgress？

private class ConversationTask extends AsyncTask<String, Void, String> {
    String textResponse = new String();
    @Override
    protected String doInBackground(String... params) {
        System.out.println("in doInBackground");
        MessageRequest newMessage = new MessageRequest.Builder().inputText(params[0]).context(context).build();
        // async
        GLS_service.message("xxxxxxxxx", newMessage).enqueue(new ServiceCallback<MessageResponse>() {
            @Override
            public void onResponse(MessageResponse response) {
                context = response.getContext();
                textResponse = response.getText().get(0);
                action5(textResponse);
                System.out.println(textResponse);

            }
            @Override
            public void onFailure(Exception e) {
            }
        });
        return textResponse;
    }@Override protected void onPostExecute(String result) {
        reply.setText(textResponse);
    }
}

请帮忙。

Answer 1

我认为您不必使用 AsyncTask。

你可以这样做：

YourTask.java

public class YourTask implements Runnable {

    private Handler handler;
    private TextView textView;

    public YourTask(TextView textView){
          this.textView = textView;
          handler = new Handler();
    }

    @Override
    public void run() {
        MessageRequest newMessage = new MessageRequest.Builder().inputText(params[0]).context(context).build();

        GLS_service.message("xxxxxxxxx", newMessage).enqueue(new ServiceCallback<MessageResponse>() {

            @Override
            public void onResponse(MessageResponse response) {
                final String textResponse = response.getText().get(0);
                handler.post(new Runnable() {
                             @Override
                             public void run() {
                                   if(textView != null){
                                      textView.setText(textResponse);
                                   }
                             }
                });
            }

            @Override
            public void onFailure(Exception e) {
            }
        });    
    }

}

现在如何使用它：

SomeActivity.java

...
textView = (TextView) findViewById(R.id.textView);
...

Thread thread = new Thread(new YourTask(textView));
thread.start();
...

不过，如果您想在 Asynktask 中执行此操作，请尝试此操作

private class ConversationTask extends AsyncTask<String, Void, Void> {

    private Handler handler;

    public ConversationTask(){
           handler = new Handler();
    }

    @Override
    protected Void doInBackground(String... params) {
        MessageRequest newMessage = new MessageRequest.Builder().inputText(params[0]).context(context).build();

        GLS_service.message("xxxxxxxxx", newMessage).enqueue(new ServiceCallback<MessageResponse>() {
            @Override
            public void onResponse(MessageResponse response) {
                final String textResponse = response.getText().get(0);
                handler.post(new Runnable() {
                         @Override
                         public void run() {
                               if(reply != null){
                                  reply.setText(textResponse);
                               }
                         }
                });                 
            }
            @Override
            public void onFailure(Exception e) {
            }
        });
        return null;
    }
}

希望对您有所帮助

UI 线程问题的竞争条件。

Race condition with UI thread issue.

java

android

android-studio

ibm-watson