Django TypeError: logout() takes at least 1 argument (1 given)
Django TypeError: logout() takes at least 1 argument (1 given)
我不明白为什么这个 url 给我一个错误:
from django.contrib.auth import views as auth_views
from django.core.urlresolvers import reverse_lazy
...
url(r'^logout/$', auth_views.logout(next_page=reverse_lazy("dashboard:operations_login")), name="operations_logout"),
...
错误是:
Django TypeError: logout() takes at least 1 argument (1 given)
您在 url 定义中直接调用注销视图。
如果你需要传递参数,你应该在单独的字典中进行:
url(r'^logout/$',
auth_views.logout,
{'next_page': reverse_lazy("dashboard:operations_login")},
name="operations_logout"),
我不明白为什么这个 url 给我一个错误:
from django.contrib.auth import views as auth_views
from django.core.urlresolvers import reverse_lazy
...
url(r'^logout/$', auth_views.logout(next_page=reverse_lazy("dashboard:operations_login")), name="operations_logout"),
...
错误是:
Django TypeError: logout() takes at least 1 argument (1 given)
您在 url 定义中直接调用注销视图。
如果你需要传递参数,你应该在单独的字典中进行:
url(r'^logout/$',
auth_views.logout,
{'next_page': reverse_lazy("dashboard:operations_login")},
name="operations_logout"),