Python Difflib - 如何获得不同的序列，如 PHP 不同的 Class 格式

Question

我正在阅读 python difflib 文档。根据 difflib.differ 输出是：

代码含义 '-' 序列 1 独有的行 '+' 序列 2 独有的行 ' ' 两个序列共有的行 '？ ' 两个输入序列中都不存在行

我也在 Whosebug 上阅读这个问题 Python Difflib - How to Get SDiff Sequences with "Change" Op but not be able to add a comment on the Sнаđошƒаӽ的回答。

我不太了解 Perl 的 Sdiff 是什么，但我需要调整此功能:

def sdiffer(s1, s2):
    differ = difflib.Differ()
    diffs = list(differ.compare(s1, s2))

    i = 0
    sdiffs = []
    length = len(diffs)
    while i < length:
        line = diffs[i][2:]
        if diffs[i].startswith('  '):
            sdiffs.append(('u', line))

        elif diffs[i].startswith('+ '):
            sdiffs.append(('+', line))

        elif diffs[i].startswith('- '):
            if i+1 < length and diffs[i+1].startswith('? '): # then diffs[i+2] starts with ('+ '), obviously
                sdiffs.append(('c', line))
                i += 3 if i + 3 < length and diffs[i + 3].startswith('? ') else 2

            elif diffs[i+1].startswith('+ ') and i+2<length and diffs[i+2].startswith('? '):
                sdiffs.append(('c', line))
                i += 2
            else:
                sdiffs.append(('-', line))
        i += 1
    return sdiffs

像PHP Diff Class

上面的函数我试过了，它 return UNCHANGE、ADDED 和 DELETED 的值。 DELETED 更复杂，有 4 种不同情况，即：

情况一:插入一些字符修改的行

- The good bad
+ The good the bad
?          ++++

情况2：删除部分字符修改行

- The good the bad
?          ----
+ The good bad

案例3：修改行删除插入and/or替换部分字符：

- The good the bad and ugly
?      ^^ ----
+ The g00d bad and the ugly
?      ^^          ++++

情况4：该行被删除

- The good the bad and the ugly
+ Our ratio is less than 0.75!

我不知道如何在这段代码中进行调整

elif diffs[i].startswith('- '):
        if i+1 < length and diffs[i+1].startswith('? '): # then diffs[i+2] starts with ('+ '), obviously
            sdiffs.append(('c', line))
            i += 3 if i + 3 < length and diffs[i + 3].startswith('? ') else 2

        elif diffs[i+1].startswith('+ ') and i+2<length and diffs[i+2].startswith('? '):
            sdiffs.append(('c', line))
            i += 2
        else:
            sdiffs.append(('-', line))

跳过'?'线。我只想在没有插入新行时附加（-），如果调用插入的新行则附加（+）。

Answer 1

我想我已经完成了我想要的 PHP 差异输出。

def sdiffer(s1, s2):
    differ = difflib.Differ()
    diffs = list(differ.compare(s1, s2))

    i = 0
    sdiffs = []
    length = len(diffs)
    sequence = 0
    while i < length:
        line = diffs[i][2:]
        if diffs[i].startswith('  '):
            sequence +=1
            sdiffs.append((sequence,'u', line))

        elif diffs[i].startswith('+ '):
            sequence +=1
            sdiffs.append((sequence,'+', line))

        elif diffs[i].startswith('- '):
            sequence +=1
            sdiffs.append((sequence,'-',diffs[i][2:]))
            if i+1 < length and diffs[i+1].startswith('? '):
                if diffs[i+3].startswith('?') and i+3 < length : # case 3
                    sequence +=1
                    sdiffs.append((sequence,'+',diffs[i+2][2:]))
                    i+=3
                elif diffs[i+2].startswith('?') and i+2 < length: # case 2
                    sequence +=1
                    sdiffs.append((sequence,'+',diffs[i+2][2:]))
                    i+=2
            elif diffs[i+1].startswith('+ ') and i+2<length and diffs[i+2].startswith('? '): # case 1
                sequence +=1
                sdiffs.append((sequence,'+', diffs[i+1][2:]))
                i += 2
            else: # the line is deleted and inserted new line # case 4
                sequence +=1
                sdiffs.append((sequence,'+', diffs[i+1][2:]))
                i+=1   
        i += 1
    return sdiffs

Python Difflib - 如何获得不同的序列，如 PHP 不同的 Class 格式

Python Difflib - How to get diff sequneces like PHP Diff Class format

php

python

perl

difflib