enzyme mocha AssertionError: expected 0 to equal 21

Question

为应用程序编写一些单元测试并在描述块中碰壁。

/* eslint-env mocha */
const React = require('react')
const chai = require('chai')
const { expect } = chai
const Search = require('../js/Search')
const ShowCard = require('../js/ShowCard')
const enzyme = require('enzyme')
const { shallow } = enzyme
const data = require('../public/data')

describe('<Search />', () => {
  it('should render as many shows as there are data for', () => {
    const wrapper = shallow(<Search />)
    expect(wrapper.find(ShowCard).length).to.equal(data.shows.length)
    console.log(wrapper.debug())
  })
})

搜索组件中的代码正在像这样呈现 ShowCard：

<div className='shows'>
  {data.shows
    .filter((show) => `${show.title} ${show.description}`.toUpperCase().indexOf(this.state.searchTerm.toUpperCase()) >= 0)
    .map((show, index) => (
      <ShowCard {...show} key={index} id={index} />
  ))}
</div>

(wrapper.find(ShowCard).length) 应该等于 (data.shows.length)，但它给出了这个错误：

  <Search /> should render as many shows as there are data for:

  AssertionError: expected 0 to equal 21
  + expected - actual

  -0
  +21

  at Context.<anonymous> (App.spec.js:19:45)

根据上述错误，问题开始于预期 equal(data.shows.length) 但我认为这没有错。谁能指出我正确的方向？

Answer 1

哇，好尴尬。我将 Search 构造函数的输入值的状态设置为 "default search term" - 从而防止出现任何搜索结果，直到该字符串被手动从输入中删除。

替换为空字符串解决了问题。现在所有测试都通过了。

enzyme mocha AssertionError: expected 0 to equal 21

enzyme mocha AssertionError: expected 0 to equal 21

node.js

reactjs

mocha.js

chai

enzyme