从 URL 中检索 XML 不写前几行

Question

我目前正在为大学编写一个基本的天气应用程序，其中包括从 BBC 天气 RSS 提要中检索天气信息。

我已将其全部设置为将 RSS 提要输出到文件 (output.xml)，然后解析器 class 将使用该文件构建树。

但是我得到 The markup in the document following the root element must be well- formed. 当我运行它时出错。

检查下载的 XML 文件后，我发现前两个节点丢失了。

这是下载的 XML:

<channel>
    <atom:link href="http://open.live.bbc.co.uk/weather/feeds/en/2656397/observations.rss" rel="self" type="application/rss+xml" />
    <title>BBC Weather - Observations for  Bangor, United Kingdom</title>
    <link>http://www.bbc.co.uk/weather/2656397</link>
    <description>Latest observations for Bangor from BBC Weather, including weather, temperature and wind information</description>
    <language>en</language>
    <copyright>Copyright: (C) British Broadcasting Corporation, see http://www.bbc.co.uk/terms/additional_rss.shtml for more details</copyright>
    <pubDate>Thu, 12 Mar 2015 05:35:08 +0000</pubDate>
    <item>
      <title>Thursday - 05:00 GMT: Thick Cloud, 10°C (50°F)</title>
      <link>http://www.bbc.co.uk/weather/2656397</link>
      <description>Temperature: 10°C (50°F), Wind Direction: South Easterly, Wind Speed: 8mph, Humidity: 90%, Pressure: 1021mb, Falling, Visibility: Very Good</description>
      <pubDate>Thu, 12 Mar 2015 05:35:08 +0000</pubDate>
      <guid isPermaLink="false">http://www.bbc.co.uk/weather/2656397-2015-03-12T05:35:08.000Z</guid>
      <georss:point>53.22647 -4.13459</georss:point>
    </item>
  </channel>
</rss>

XML在<channel>节点之前应该有如下两个节点：

<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:atom="http://www.w3.org/2005/Atom" xmlns:georss="http://www.georss.org/georss" version="2.0">

这是我用来检索 XML 文件的代码：

public static void main(String[] args) throws SAXException, IOException, XPathExpressionException {
    URL url = new URL("http://open.live.bbc.co.uk/weather/feeds/en/2656397/observations.rss");
    URLConnection con = url.openConnection();
    StringBuilder builder;
    try (BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()))) {

        builder = new StringBuilder();
        String line;

        if (!in.readLine().isEmpty()) {
            line = in.readLine();
        }

        while ((line = in.readLine()) != null) {
            builder.append(line).append("\n");
        }

        String input = builder.toString();

        BufferedWriter out = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(new File("output.xml"))));
        out.write(input);
        out.flush();
    }
    try {
        WeatherParser parser = new WeatherParser();
        System.out.println(parser.parse("output.xml"));
    } catch (ParserConfigurationException ex) {
    }
}

下面是解析 XML (WeatherParser.java) 的代码：

public class WeatherParser {

    public WeatherParser() throws ParserConfigurationException {
        xpfactory = XPathFactory.newInstance();
        path = xpfactory.newXPath();
        dbfactory = DocumentBuilderFactory.newInstance();
        builder = dbfactory.newDocumentBuilder();
    }

    public String parse(String fileName) throws SAXException, IOException, XPathExpressionException {
        File f = new File(fileName);
        org.w3c.dom.Document doc = builder.parse(f);
        StringBuilder info = new StringBuilder();
        info.append(path.evaluate("/channel/item/title", doc));
        return info.toString();
    }

    private DocumentBuilderFactory dbfactory;
    private DocumentBuilder builder;
    private XPathFactory xpfactory;
    private XPath path;
}

希望提供的信息足够了。

Answer 1

缺少前两行是因为您阅读了但没有阅读"save"
删除它，它将起作用。

    if (!in.readLine().isEmpty()) {
        line = in.readLine();
    }

在 if 中你正在阅读第一行 (<?xml....) 但你没有保留它。
line = in.readLine(); 获得第二个，但是当您输入 while 时，您会丢失 line 变量中的内容。

Answer 2

首先，您不得操纵服务器发送给您的数据流。删除 StringBuilder。如果要将 XML 保存到磁盘，请逐字写入：

URL url = new URL("http://open.live.bbc.co.uk/weather/feeds/en/2656397/observations.rss");
URLConnection con = url.openConnection();
InputStream in = conn.getInputStream();
FileOutputStream out = new FileOutputStream("output.xml");

byte[] b = new byte[1024];
int count;
while ((count = in.read(b)) >= 0) {
    out.write(b, 0, count);
}
out.flush(); out.close(); in.close();

事实上，您根本不需要将其写入磁盘。您可以直接从输入流构建 XML 文档。

public static Document readXml(InputStream is) throws SAXException, ParserConfigurationException, IOException {
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();

    dbf.setValidating(false);
    dbf.setIgnoringComments(false);
    dbf.setIgnoringElementContentWhitespace(true);
    dbf.setNamespaceAware(true);

    DocumentBuilder db = dbf.newDocumentBuilder();
    return db.parse(is);
}

使您能够

public static void main (String[] args) throws java.lang.Exception
{
    URL observationsUrl = new URL("http://open.live.bbc.co.uk/weather/feeds/en/2656397/observations.rss");
    Document observations = readXml(observationsUrl.openConnection().getInputStream());

    XPathFactory xpf = XPathFactory.newInstance();
    XPath xpath = xpf.newXPath();

    String title = xpath.evaluate("/rss/channel/title", observations);
    System.out.println(title);

    XPathExpression rssitemsExpr = xpath.compile("/rss/channel/item");

    NodeList items = (NodeList)rssitemsExpr.evaluate(observations, XPathConstants.NODESET);
    for (int i = 0; i < items.getLength(); i++) {
        System.out.println(xpath.evaluate("./title", items.item(i)));
    }
}

我的输出：

BBC Weather - Observations for  Bangor, United Kingdom
Thursday - 06:00 GMT: Thick Cloud, 11°C (52°F)

从 URL 中检索 XML 不写前几行

Retrieving XML from URL not writing first couple of lines

java

xml

parsing

dom