如何通过 Laravel 检查 URL 是否存在?

How can I check if a URL exists via Laravel?

我确实看过这个答案:

How can I check if a URL exists via PHP?

但是,我想知道 Laravel 中是否存在可以检查 URL 是否存在(不是 404)的方法?

我假设您想检查是否有一条路线匹配某个 URL。

$routes = Route::getRoutes();
$request = Request::create('the/url/you/want/to/check');
try {
    $routes->match($request);
    // route exists
}
catch (\Symfony\Component\HttpKernel\Exception\NotFoundHttpException $e){
    // route doesn't exist
}

试试这个功能

function checkRoute($route) {
    $routes = \Route::getRoutes()->getRoutes();
    foreach($routes as $r){
        if($r->getUri() == $route){
            return true;
        }
    }

    return false;
}

没有特别的laravel功能,但是你可以试试这个

 function urlExists($url = NULL)
    {
        if ($url == NULL) return false;
        $ch = curl_init($url);
        curl_setopt($ch, CURLOPT_TIMEOUT, 5);
        curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 5);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        $data = curl_exec($ch);
        $httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
        curl_close($ch);
        return ($httpcode >= 200 && $httpcode < 300) ? true : false;        
   }

由于您提到要检查外部 URL(例如 https://google.com),而不是应用内的路由,您可以使用 Http facade in Laravel 这样 (https://laravel.com/docs/master/http-client):

use Illuminate\Support\Facades\Http;

$response = Http::get('https://google.com');

if( $response->successful() ) {
    // Do something ...
}