使用 curl 获取 http 响应 header

Question

我使用 curl --interface ip_goes here -I -L https://www.youtube.com/ 获取 http headers 但我想将 HTTP/1.1 200 OK 存储在变量中。我可以用 preg_match 来做，但我想知道是否有更有效的解决方案

HTTP/1.1 200 OK
Date: Fri, 09 Jan 2015 05:49:12 GMT
Server: gwiseguy/2.0
Content-Type: text/html; charset=utf-8
Cache-Control: no-cache
X-Frame-Options: SAMEORIGIN
Expires: Tue, 27 Apr 1971 19:44:06 EST
P3P: CP="This is not a P3P policy! See http://support.google.com/accounts/answer/151657?hl=en for more info."
X-XSS-Protection: 1; mode=block; report=https://www.google.com/appserve/security-bugs/log/youtube
X-Content-Type-Options: nosniff
Alternate-Protocol: 443:quic,p=0.02
Transfer-Encoding: chunked
Set-Cookie: YSC=zCtzROldgfs; path=/; domain=.youtube.com; HttpOnly
Set-Cookie: VISITOR_INFO1_LIVE=Oz-yH5fLujM; expires=Wed, 09-Sep-2015 17:42:11 GMT; path=/; domain=.youtube.com

Answer 1

使用这个命令

curl --interface ip_goes_here -s -I -L https://www.youtube.com/ | head -1

注意额外的 -s 表示静音

Answer 2

试试这个：

$str="HTTP/1.1 200 OK
Date: Fri, 09 Jan 2015 05:49:12 GMT
Server: gwiseguy/2.0
Content-Type: text/html; charset=utf-8
Cache-Control: no-cache
X-Frame-Options: SAMEORIGIN 
more string....";
    $a=explode("\n",$str);
    var_dump($a[0]);

输出： string 'HTTP/1.1 200 OK'

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