查找重叠的正则表达式匹配项

Question

我想查找给定字符串中的所有匹配项，包括重叠匹配项。我怎样才能实现它？

# Example
"a-b-c-d".???(/\w-\w/)  # => ["a-b", "b-c", "c-d"] expected

# Solution without overlapped results
"a-b-c-d".scan(/\w-\w/) # => ["a-b", "c-d"], but "b-c" is missing

Answer 1

在正先行中使用捕获：

"a-b-c-d".scan(/(?=(\w-\w))/).flatten
 # => ["a-b", "b-c", "c-d"]

见Ruby demo

Answer 2

我建议使用非正则表达式解决方案：

"a-b-c-d".delete('-').each_char.each_cons(2).map { |s| s.join('-') }
  #=> ["a-b", "b-c", "c-d"]

或

"a-b-c-d".each_char.each_cons(3).select.with_index { |_,i| i.even? }.map(&:join)
  #=> ["a-b", "b-c", "c-d"]

或

enum = "a-b-c-d".each_char
a = []
loop do
  a << "%s%s%s" % [enum.next, enum.next, enum.peek]
end
a #=> ["a-b", "b-c", "c-d"]

查找重叠的正则表达式匹配项

Find overlapping Regexp matches

ruby

regex

overlap