函数的名称。它是指向该函数的指针吗？

Question

当我们使用函数名传递参数时，我们是在使用指向该函数的指针吗？

示例：

int foo(int a, int b);

int main(void)
{
    int a = foo(1,3); //foo() it's a pointer to the function foo()?
    return 0;
}

Answer 1

您要查找的术语是功能指示符。它不是 pointer 类型，但大多数时候，它是 converted to one.

引用 C11 标准，章节 §6.3.2.1，（强调我的）

A function designator is an expression that has function type. Except when it is the operand of the sizeof operator, the _Alignof operator,65) or the unary & operator, a function designator with type ‘‘function returning type’’ is converted to an expression that has type ‘‘pointer to function returning type’’.

相关，来自规范的 "function call" 部分，第 6.5.2.2 章

The expression that denotes the called function 92) shall have type pointer to function returning void or returning a complete object type other than an array type.

这告诉我们，在函数调用中，指示符实际上被转换为指针。

函数的名称。它是指向该函数的指针吗？

The name of a function. is it a pointer to that function?

c

function-pointers

function

function-calls