Php

Question

我正在尝试根据最接近现在的日期更改 $showThis。如何比较时差？目前 $interval1 > $interval2 不起作用。我知道正在计算差异，但我不确定如何比较两者。

$currentTime = new DateTime("now");
$wednesday = new DateTime('wednesday 10:59pm');
$saturday = new DateTime('saturday 10:59pm');
$interval1 = $currentTime->diff($wednesday);
$interval2 = $currentTime->diff($saturday);

if($interval1 > $interval2){
    $showThis = $saturday->format('D m/d/Y h:i A');
}
if($interval1 < $interval2){
    $showThis = $wednesday->format('D m/d/Y h:i A');
}

Answer 1

使用getTimestamp方法。

$interval1 = $wednesday->getTimestamp() - $currentTime->getTimestamp();
$interval2 = $saturday->getTimestamp() - $currentTime->getTimestamp();

Answer 2

在比较它们之前，您应该将间隔添加到 0 日期以将间隔转换为秒：

$currentTime = new DateTime("now");
$wednesday = new DateTime('wednesday 10:59pm');
$saturday = new DateTime('saturday 10:59pm');

$interval1 = $currentTime->diff($wednesday);
$interval2 = $currentTime->diff($saturday);

$seconds1 = date_create('@0')->add($interval1)->getTimestamp();
$seconds2 = date_create('@0')->add($interval2)->getTimestamp();

if ($seconds1 > $seconds2){
    $showThis = $saturday->format('D m/d/Y h:i A');
}
else {
    $showThis = $wednesday->format('D m/d/Y h:i A');
}

echo $showThis;

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