在 JSON.stringify() 的输出中隐藏空值

Question

In my code, all of the info from a Postgres table row are stringified when a specific rowID is selected.

var jsonRes = result.message.rows;

document.getElementById('panel').innerHTML = '<pre>' + JSON.stringify(jsonRes[0], null, "\t") + '</pre>'

结果看起来像这样：

{
  "ogc_fid": 143667,
  "relkey": 288007,
  "acct": "000487000A0010000",
  "recacs": "12.5495 AC",
  "shape_star": 547131.567383,
  "shape_stle": 3518.469618,
  "objectid": 307755,
  "zone_dist": "MU-3",
  "pd_num": null,
  "council_da": null,
  "long_zone_": "MU-3",
  "globalid": "{D5B006E8-716A-421F-A78A-2D71ED1DC118}",
  "ord_num": null,
  "notes": null,
  "res_num": null,
  "effectived": 1345766400000,
  "shape.star": 629707.919922,
  "shape.stle": 3917.657332,
  "case_numbe": null,
  "common_nam": null,
  "districtus": null 
}

我是 JS 的新手，想知道是否有一种简单的方法可以完全排除包含空值的列 - 一个大致如下所示的函数：

function hide(jsonObject) {
    if (property === null) {
      hide property
  } else {
      return str
  }
}

所以最后，面板中的对象是这样的：

{
  "ogc_fid": 143667,
  "relkey": 288007,
  "acct": "000487000A0010000",
  "recacs": "12.5495 AC",
  "shape_star": 547131.567383,
  "shape_stle": 3518.469618,
  "objectid": 307755,
  "zone_dist": "MU-3",
  "long_zone_": "MU-3",
  "globalid": "{D5B006E8-716A-421F-A78A-2D71ED1DC118}",
  "effectived": 1345766400000,
  "shape.star": 629707.919922,
  "shape.stle": 3917.657332
}

Answer 1

试试这个：

function getCleanObject(jsonObject) {
    var clone = JSON.parse(JSON.stringify(jsonObject))
    for(var prop in clone)
       if(clone[prop] == null)
           delete clone[prop];
    return JSON.stringify(clone);
}

Answer 2

如果您想保留您的初始对象，您可以像这样创建一个新对象

  var object = {
    "ogc_fid": 143667,
    "relkey": 288007,
    "acct": "000487000A0010000",
    "recacs": "12.5495 AC",
    "shape_star": 547131.567383,
    "shape_stle": 3518.469618,
    "objectid": 307755,
    "zone_dist": "MU-3",
    "pd_num": null,
    "council_da": null,
    "long_zone_": "MU-3",
    "globalid": "{D5B006E8-716A-421F-A78A-2D71ED1DC118}",
    "ord_num": null,
    "notes": null,
    "res_num": null,
    "effectived": 1345766400000,
    "shape.star": 629707.919922,
    "shape.stle": 3917.657332,
    "case_numbe": null,
    "common_nam": null,
    "districtus": null
  };

  var newObj = {};

  Object.keys(object).forEach(function(key) {
    if (object[key] !== null)
      newObj[key] = object[key];
  });
  console.log(newObj);

Answer 3

感谢您的回复。我刚刚意识到 JSON.stringify() 有一个 REPLACER 参数 (info here)

所以我刚刚添加：

function replacer(key, value) {
  // Filtering out properties
  if (value === null) {
    return undefined;
  }
  return value;
}

document.getElementById('panel').innerHTML =
  '<pre>' +
    JSON.stringify(jsonRes[0], replacer, "\t") +
  '</pre>'
;

Answer 4

你可以这样做：

let x = {
  'x1':0,
  'x2':null,
  'x3':"xyz", 
  'x4': null
}

console.log(JSON.stringify(x, (key, value) => {
  if (value !== null) return value
}))

在 JSON.stringify() 的输出中隐藏空值

Hide null values in output from JSON.stringify()

javascript

json

stringify