WPF 中的简单弹出对话框(覆盖 Window)
Simple popup dialog in WPF (overlay inside Window)
我正在开发模式对话框弹出窗口 (我不确定确切的 UX 术语) 内嵌显示在控件内部或 window 背景变暗。
视觉示例
我尝试的是将 <ContentPresenter />
放入弹出窗口的 XAML 中,然后像这样实例化它:
<local:Popup Grid.RowSpan="2">
<TextBlock Text="Popup test..." />
</local:Popup>
但是,XAML 替换了整个 Popup XAML 而不是放置在 ContentPresenter 所在的位置。
问:这里的ContentPresenter如何正确使用?
Popup.xaml
<ContentControl
x:Class="[...].Popup"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:local="clr-namespace:[...]"
mc:Ignorable="d" d:DesignWidth="300" d:DesignHeight="300">
<Grid Background="#7f000000">
<Grid Background="White" HorizontalAlignment="Center" VerticalAlignment="Center">
<StackPanel Margin="20">
<TextBlock Text="{Binding Title, RelativeSource={RelativeSource AncestorType=UserControl}}" FontSize="20" />
<ContentPresenter />
</StackPanel>
</Grid>
</Grid>
</ContentControl>
Popup.xaml.cs
using System.Windows;
namespace [...]
{
public partial class Popup : ContentControlBase
{
public static DependencyProperty TitleProperty = DependencyProperty.Register(nameof(Title), typeof(string), typeof(Popup));
public string Title
{
get
{
return (string)GetValue(TitleProperty);
}
set
{
SetValue(TitleProperty, value);
}
}
public Popup()
{
InitializeComponent();
}
}
}
您的 Popup 内容应定义为 ControlTemplate,以便 ContentPresenter 在这里按预期工作。请参考以下示例代码。
Popup.xaml:
<ContentControl
x:Class="WpfApplication1.Popup"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:local="clr-namespace:WpfApplication1"
mc:Ignorable="d" d:DesignWidth="300" d:DesignHeight="300"
x:Name="popup">
<ContentControl.Template>
<ControlTemplate TargetType="local:Popup">
<Grid Background="#7f000000">
<Grid Background="White" HorizontalAlignment="Center" VerticalAlignment="Center">
<StackPanel Margin="20">
<TextBlock Text="{Binding Title, ElementName=popup}" FontSize="20" />
<ContentPresenter />
</StackPanel>
</Grid>
</Grid>
</ControlTemplate>
</ContentControl.Template>
Popup1.xaml.cs.
public partial class Popup : ContentControl
{
public static DependencyProperty TitleProperty = DependencyProperty.Register(nameof(Title), typeof(string), typeof(Popup));
public string Title
{
get
{
return (string)GetValue(TitleProperty);
}
set
{
SetValue(TitleProperty, value);
}
}
public Popup()
{
InitializeComponent();
}
}
}
Window1.xaml:
<local:Popup Title="Title...">
<TextBlock>Text...</TextBlock>
</local:Popup>
我正在开发模式对话框弹出窗口 (我不确定确切的 UX 术语) 内嵌显示在控件内部或 window 背景变暗。
视觉示例
我尝试的是将 <ContentPresenter />
放入弹出窗口的 XAML 中,然后像这样实例化它:
<local:Popup Grid.RowSpan="2">
<TextBlock Text="Popup test..." />
</local:Popup>
但是,XAML 替换了整个 Popup XAML 而不是放置在 ContentPresenter 所在的位置。
问:这里的ContentPresenter如何正确使用?
Popup.xaml
<ContentControl
x:Class="[...].Popup"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:local="clr-namespace:[...]"
mc:Ignorable="d" d:DesignWidth="300" d:DesignHeight="300">
<Grid Background="#7f000000">
<Grid Background="White" HorizontalAlignment="Center" VerticalAlignment="Center">
<StackPanel Margin="20">
<TextBlock Text="{Binding Title, RelativeSource={RelativeSource AncestorType=UserControl}}" FontSize="20" />
<ContentPresenter />
</StackPanel>
</Grid>
</Grid>
</ContentControl>
Popup.xaml.cs
using System.Windows;
namespace [...]
{
public partial class Popup : ContentControlBase
{
public static DependencyProperty TitleProperty = DependencyProperty.Register(nameof(Title), typeof(string), typeof(Popup));
public string Title
{
get
{
return (string)GetValue(TitleProperty);
}
set
{
SetValue(TitleProperty, value);
}
}
public Popup()
{
InitializeComponent();
}
}
}
您的 Popup 内容应定义为 ControlTemplate,以便 ContentPresenter 在这里按预期工作。请参考以下示例代码。
Popup.xaml:
<ContentControl
x:Class="WpfApplication1.Popup"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:local="clr-namespace:WpfApplication1"
mc:Ignorable="d" d:DesignWidth="300" d:DesignHeight="300"
x:Name="popup">
<ContentControl.Template>
<ControlTemplate TargetType="local:Popup">
<Grid Background="#7f000000">
<Grid Background="White" HorizontalAlignment="Center" VerticalAlignment="Center">
<StackPanel Margin="20">
<TextBlock Text="{Binding Title, ElementName=popup}" FontSize="20" />
<ContentPresenter />
</StackPanel>
</Grid>
</Grid>
</ControlTemplate>
</ContentControl.Template>
Popup1.xaml.cs.
public partial class Popup : ContentControl
{
public static DependencyProperty TitleProperty = DependencyProperty.Register(nameof(Title), typeof(string), typeof(Popup));
public string Title
{
get
{
return (string)GetValue(TitleProperty);
}
set
{
SetValue(TitleProperty, value);
}
}
public Popup()
{
InitializeComponent();
}
}
}
Window1.xaml:
<local:Popup Title="Title...">
<TextBlock>Text...</TextBlock>
</local:Popup>