MYSQL 从多个表中提取多个值

MYSQL Pulling multiple values from multiple tables

请原谅我的标题选择不当,我不知道该用什么来标记这个问题,但相信我可以解释。

我在产品 table 和商店 table 之间建立了多对多关系。

table name: products
+-------+------------------+------+-----+---------+----------------+
| Field | Type             | Null | Key | Default | Extra          |
+-------+------------------+------+-----+---------+----------------+
| id    | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| name  | varchar(200)     | NO   |     | NULL    |                |
| sku   | varchar(10)      | NO   |     | NULL    |                |
| units | int(5)           | YES  |     | NULL    |                |
+-------+------------------+------+-----+---------+----------------+

table name: stores
+----------+------------------+------+-----+---------+----------------+
| Field    | Type             | Null | Key | Default | Extra          |
+----------+------------------+------+-----+---------+----------------+
| id       | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| number   | int(5)           | NO   |     | NULL    |                |
| location | varchar(50)      | NO   |     | NULL    |                |
| phone    | varchar(10)      | YES  |     | NULL    |                |
+----------+------------------+------+-----+---------+----------------+


table name: products_stores
+-------+------------------+------+-----+---------+-------+
| Field | Type             | Null | Key | Default | Extra |
+-------+------------------+------+-----+---------+-------+
| pID   | int(10) unsigned | NO   | PRI | NULL    |       |
| sID   | int(10) unsigned | NO   | PRI | NULL    |       |
+-------+------------------+------+-----+---------+-------+

我是 运行 查询以显示其 ID = 1

的商店中可用的所有产品
SELECT p.name, p.sku 
FROM products p 
  INNER JOIN products_stores ps
    ON p.id = ps.pID 
WHERE ps.sID = 1;

我对这个查询没问题,得到了我想要的结果。但是,在我的显示结果中,我还想显示每个结果行的商店位置值。我以为我可以在我的 FROM 语句中包含逗号分隔,例如:

SELECT p.name, p.sku, s.location
FROM products p, stores s
  INNER JOIN products_stores ps
    ON p.id = ps.pID
WHERE ps.sID = 1;

但是这不起作用。我相信答案很简单,我会继续研究解决方案。我想我会把它扔掉,希望有人能引导我朝着正确的方向前进。

谢谢。

SELECT 
  p.name,
  p.sku,
  s.location 
FROM
  products p,
  stores s,
  products_stores ps 
WHERE p.id = ps.pID 
  AND s.sID = ps.sID 
  AND ps.sID = 1 ;

使用显式 JOIN,隐式 JOIN 已弃用(并且不太清楚)

SELECT p.name, p.sku ,s.location
FROM products p 
  INNER JOIN products_stores ps
    ON p.id = ps.pID 
INNER JOIN stores s
ON s.ID=ps.sID
WHERE ps.sID = 1;