水印上传图片不调整图片宽度高度

Question

所以我的以下代码的工作方式就像我上传图片一样，它会将图片调整为 720x450，然后为其添加水印。但是我不想修改宽高，把水印放在任意尺寸图片的右下角

是否有人可以帮助我？

$image_path = "../images/watermark.png";
function watermark_image($oldimage_name, $new_image_name){
    global $image_path;
    list($owidth,$oheight) = getimagesize($oldimage_name);
    $width = 720; $height = 450;    
    $im = imagecreatetruecolor($width, $height);
    $img_src = imagecreatefromjpeg($oldimage_name);
    imagecopyresampled($im, $img_src, 0, 0, 0, 0, $width, $height, $owidth, $oheight);
    $watermark = imagecreatefrompng($image_path);
    list($w_width, $w_height) = getimagesize($image_path);        
    $pos_x = $width - $w_width; 
    $pos_y = $height - $w_height;
    imagecopy($im, $watermark, $pos_x, $pos_y, 0, 0, $w_width, $w_height);
    imagejpeg($im, $new_image_name, 90);
    imagedestroy($im);
    unlink($oldimage_name);
    return true;
}

感谢您的帮助和时间。

Answer 1

您手动提供高度和宽度，只需分配图像的原始高度和宽度

$image_path = "../images/watermark.png";
function watermark_image($oldimage_name, $new_image_name){
    global $image_path;
    list($owidth,$oheight) = getimagesize($oldimage_name);
    $width = $owidth; $height = $oheight;    
    $im = imagecreatetruecolor($width, $height);
    $img_src = imagecreatefromjpeg($oldimage_name);
    imagecopyresampled($im, $img_src, 0, 0, 0, 0, $width, $height, $owidth, $oheight);
    $watermark = imagecreatefrompng($image_path);
    list($w_width, $w_height) = getimagesize($image_path);        
    $pos_x = $width - $w_width; 
    $pos_y = $height - $w_height;
    imagecopy($im, $watermark, $pos_x, $pos_y, 0, 0, $w_width, $w_height);
    imagejpeg($im, $new_image_name, 90);
    imagedestroy($im);
    unlink($oldimage_name);
    return true;
}

试试这会如您所愿。

查看更多信息http://php.net/manual/en/image.examples-watermark.php

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