透视 table 数据

Question

我有以下数据

  NAME | RIGHTS |
Steven | add |
Steven | update |
Steven | delete |
Mark   | update |
Mark   | delete |
Joseph | don’t have Rights |
Spike  | add |
Spike  | update |
Spike  | delete |

而这个数据，我想操作为

  NAMEs | don’t have Rights | add| update | delete |

 Steven | 0 |1|1|1|

 Mark   |0|0|1|1|

 Joseph |1|0|0|0|

 Spike  |0|1|1|1|

请注意，我不知道权限类型，它可以超过 100

Answer 1

**Using pivot to get that result :**

CREATE TABLE #details(Id INT,NAME VARCHAR(100), RIGHTS VARCHAR(100))
INSERT INTO #details( Id ,NAME , RIGHTS )
SELECT 1,'Steven','add' UNION ALL
SELECT 1,'Steven','update' UNION ALL
SELECT 1,'Steven','delete' UNION ALL
SELECT 1,'Mark','update' UNION ALL
SELECT 1,'Mark','delete' UNION ALL
SELECT 1,'Joseph','don’t have Rights' UNION ALL
SELECT 1,'Spike','add' UNION ALL
SELECT 1,'Spike','update' UNION ALL
SELECT 1,'Spike','delete' 

SELECT *
FROM 
(
  SELECT  NAME , RIGHTS ,Id
  FROM #details
)A
PIVOT
(
    MAX(Id) FOR RIGHTS IN ([don’t have Rights],[add],[update],[delete])
)pvt

**For Dynamic pivot use below query :** 

DECLARE @DynamicCol VARCHAR(MAX) = '',@DynamicPvt VARCHAR(MAX) = ''

SELECT @DynamicCol = 
(
  SELECT STUFF ((SELECT DISTINCT ',' + '[' + RTRIM(RIGHTS) + ']' FROM      
  #details FOR XML PATH('')),1,1,'')
)

SET @DynamicPvt = 'SELECT *
FROM 
(
 SELECT  NAME , RIGHTS ,Id
 FROM #details
)A
PIVOT
(
  MAX(Id) FOR RIGHTS IN ('+@DynamicCol+')
)pvt'

EXEC (@DynamicPvt)

Answer 2

我得到了答案

DECLARE @cols AS NVARCHAR(MAX),
   @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT distinct ',[' + Rights +']'
                    from MyTableName 
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')



set @query = 'SELECT Name,' + @cols + ' from 
             (
                SELECT Name, Rights,1 as xCount FROM MyTableName
            ) x
            pivot 
            (
                count(xCount)
                for Rights in (' + @cols + ')
            ) p '

execute(@query);

Answer 3

检查这个。

            select NAME,
            case when [don’t have Rights] is not null then 1 else 0 end as [don’t have Rights] ,
            case when [add] is not null then 1 else 0 end as [add]  ,
            case when [update] is not null then 1 else 0 end as [update]  ,
            case when [delete] is not null then 1 else 0 end as [delete] 
             from  
            (
            select * 
            from #YourTAble 
            pivot 
            (
            max(RIGHTS) for  RIGHTS in ([don’t have Rights],[delete],[update],[add])
            )a
            )b

Output :

Answer 4

Declare @Str varchar(max)
, @FinalStr varchar(max)
Set @Str=''
Select @Str = @Str + ',[' + Rights+']'
FROM (Select Distinct Rights FROM F2) A 
Set  @Str= Substring(@str,2,LEN(@Str))

SET @FinalStr =
'Select Name, ' + @Str +
'FROM F2 
PIVOT ( Count(Rights)For Rights in ( ' + @Str + ')) As A'

Exec (@FinalStr)

这将给出期望的结果，而且它也是动态的。您可以拥有的权利数量。

透视 table 数据

Pivot table data

sql

pivot

pivot-table