AnyVal 类型的通用派生与 Circe

Generic derivation of AnyVal types with Circe

我想派生值 classes 的编码器实例。使用 semiauto 机制我无法导出嵌套的 classes.

图像如下class结构

{
  case class Recipient(email: Recipient.Email, name: Recipient.Name) 

  object Recipient {
     case class Email(value: String) extends AnyVal
     case class Name(value: String) extends AnyVal
  }
}

在菊石中 shell(还要添加收件人案例 classes)

load.ivy("io.circe" %% "circe-core" % "0.6.1")
load.ivy("io.circe" %% "circe-generic" % "0.6.1")

import io.circe._
import io.circe.generic.semiauto._
import io.circe.syntax._ 

现在推导 Email 的解码器结果如预期

Recipient.Email("ab@cd.com").asJson(deriveEncoder[Recipient.Email]) 
Json = {
  "value" : "ab@cd.com"
}

推导 Encoder[Recipient] 无效

deriveDecoder[Recipient]

could not find Lazy implicit value of type 
io.circe.generic.decoding.DerivedDecoder[$sess.cmd5.Recipient]

我想做的是派生一个Encoder[Recipient.Email] returns 包装类型。如果我明确地导出编解码器,这个小片段就可以工作。

import shapeless.Unwrapped

implicit def encodeAnyVal[W <: AnyVal, U](
        implicit unwrapped: Unwrapped.Aux[W, U],
                 encoderUnwrapped: Encoder[U]): Encoder[W] = {
        Encoder.instance[W](v => encoderUnwrapped(unwrapped.unwrap(v)))
}

Recipient.Email("ab@cd.com").asJson(encodeAnyVal[Recipient.Email, String])
res11: Json = "ab@cd.com"

我还是无法推导出 Encoder[Recipient]

implicit val emailEncoder: Encoder[Recipient.Email] = encodeAnyVal[Recipient.Email, String] 
implicit val nameEncoder: Encoder[Recipient.Name] = encodeAnyVal[Recipient.Name, String]

deriveDecoder[Recipient] 
cmd14.sc:1: could not find Lazy implicit value of type io.circe.generic.decoding.DerivedDecoder[$sess.cmd5.Recipient]

有没有人做过类似的事情?

提前致谢, 向

您应该添加隐式见证实例而不是类型绑定。最终会得到这样的结果:

implicit def encodeAnyVal[W, U](
        implicit ev: W <:< Anyval,
                 unwrapped: Unwrapped.Aux[W, U],
                 encoderUnwrapped: Encoder[U]): Encoder[W] = {
        Encoder.instance[W](v => encoderUnwrapped(unwrapped.unwrap(v)))
}