人脸识别Opencv置信度负值

Question

我正在从事人脸识别项目，我已经按照 opencv 网站上的教程进行操作，并且使用了相同的数据集，但是当我测试我的程序时，我得到了奇怪的结果（置信度值），它给了我一个大值（（置信度 = 621034879.）当测试来自同一数据集的样本时，它也会给我负面的信心。为什么 Confidence 有这么大的值并且有负值？？？这是我的代码：

#include "opencv2/core/core.hpp"
#include "opencv2/contrib/contrib.hpp"
#include "opencv2/highgui/highgui.hpp"
#include <iostream>
#include <fstream>
#include <sstream>
using namespace cv;
using namespace std;
static void read_csv(const string& filename, vector<Mat>& images, vector<int>& labels, char separator = ';') {
std::ifstream file(filename.c_str(), ifstream::in);
if (!file) {
    string error_message = "No valid input file was given, please check the given filename.";
    CV_Error(CV_StsBadArg, error_message);
}
string line, path, classlabel;
while (getline(file, line)) {
    stringstream liness(line);
    getline(liness, path, separator);
    getline(liness, classlabel);
    if (!path.empty() && !classlabel.empty()) {
        images.push_back(imread(path, 0));
        labels.push_back(atoi(classlabel.c_str()));
    }
}
}


int main(int argc, const char *argv[]) {
// Check for valid command line arguments, print usage
// if no arguments were given.


// Get the path to your CSV.
string fn_csv = "C:/Users/ASUS/Documents/Visual Studio 2013/Projects/Car_Detection/a.txt";
// These vectors hold the images and corresponding labels.
vector<Mat> images;
vector<int> labels;
// Read in the data. This can fail if no valid
// input filename is given.
try {
    read_csv(fn_csv, images, labels);
}
catch (cv::Exception& e) {
    cerr << "Error opening file \"" << fn_csv << "\". Reason: " << e.msg << endl;
    // nothing more we can do
    exit(1);
}
// Quit if there are not enough images for this demo.
if (images.size() <= 1) {
    string error_message = "This demo needs at least 2 images to work. Please add more images to your data set!";
    CV_Error(CV_StsError, error_message);
}
// Get the height from the first image. We'll need this
// later in code to reshape the images to their original
// size:
int height = images[0].rows;

Mat testSample = images[images.size() - 1];
int testLabel = labels[labels.size() - 10];

images.pop_back();
labels.pop_back();

Ptr<FaceRecognizer> model = createEigenFaceRecognizer();
model->train(images, labels);
// The following line predicts the label of a given
// test image:
int predictedLabel = model->predict(testSample);

double confidence = 0.0;
model->predict(testSample, predictedLabel, confidence);
//
string result_message = format("Label = %d / confidence = %d.", predictedLabel, confidence);
cout << result_message << endl;


return 0;
}

Answer 1

这个很简单。您通过在格式字符串中使用 %d 将 confidence（即 double）转换为 int。你想要的是使用 %f （可能带有限制小数位的修饰符。

string result_message = format("Label = %d / confidence = %.2f.", predictedLabel, confidence);

人脸识别Opencv置信度负值

Face recognition Opencv confidence negative value

c++

opencv

face-recognition