是否可以使用 .NET DataContractJSONSerializer 反序列化格式不同于通常序列化的 JSON 文件？

Question

我有一个 JSON 格式的文件，它是由我无法编辑的工具生成的：

{
    "thing_name1": {
        "property1": 0,
        "property2": "sure"
    },
    "thing_name2": {
        "property1": 34,
        "property2": "absolutely"
    }
}

我正在尝试反序列化的 class 是这样的：

[DataContract]
public class Thing
{
    [DataMember]
    public String ThingName;

    [DataMember(Name="property1")]
    public int Property1;

    [DataMember(Name="property2")]
    public String Property2;
}

我需要将 "thing_name1" 和 "thing_name2" 的值放入它们各自的反序列化对象的 ThingName 数据成员中，但一直无法找到一种不编写代码的简单方法自定义（反）序列化器。或者编写一个快速 Python 脚本来编写另一个文件，但这不会很 space 有效。

Answer 1

是的，这是可能的，但您确实需要一些自定义代码才能做到这一点。

有点难看，但是你可以创建一个自定义的IDataContractSurrogate class来将JSON反序列化为Dictionary<string, Dictionary<string, object>>，然后从嵌套的值中复制值字典结构变成了List<Thing>。这是代理人需要的代码：

class MyDataContractSurrogate : IDataContractSurrogate
{
    public Type GetDataContractType(Type type)
    {
        if (type == typeof(List<Thing>))
        {
            return typeof(Dictionary<string, Dictionary<string, object>>);
        }
        return type;
    }

    public object GetDeserializedObject(object obj, Type targetType)
    {
        if (obj.GetType() == typeof(Dictionary<string, Dictionary<string, object>>) &&
            targetType == typeof(List<Thing>))
        {
            List<Thing> list = new List<Thing>();

            foreach (var kvp in (Dictionary<string, Dictionary<string, object>>)obj)
            {
                Thing thing = new Thing { ThingName = kvp.Key };
                Dictionary<string, object> propsDict = kvp.Value;

                foreach (PropertyInfo prop in GetDataMemberProperties(typeof(Thing)))
                {
                    DataMemberAttribute att = prop.GetCustomAttribute<DataMemberAttribute>();

                    object value;
                    if (propsDict.TryGetValue(att.Name, out value))
                    {
                        prop.SetValue(thing, value);
                    }
                }
                list.Add(thing);
            }

            return list;
        }
        return obj;
    }

    public object GetObjectToSerialize(object obj, Type targetType)
    {
        if (obj.GetType() == typeof(List<Thing>) &&
            targetType == typeof(Dictionary<string, Dictionary<string, object>>))
        {
            var thingsDict = new Dictionary<string, Dictionary<string, object>>();

            foreach (Thing thing in (List<Thing>)obj)
            {
                var propsDict = new Dictionary<string, object>();
                foreach (PropertyInfo prop in GetDataMemberProperties(typeof(Thing)))
                {
                    DataMemberAttribute att = prop.GetCustomAttribute<DataMemberAttribute>();
                    propsDict.Add(att.Name, prop.GetValue(thing));
                }
                thingsDict.Add(thing.ThingName, propsDict);
            }

            return thingsDict;
        }
        return obj;
    }

    private IEnumerable<PropertyInfo> GetDataMemberProperties(Type type)
    {
        return type.GetProperties().Where(p => p.CanRead && p.CanWrite && p.GetCustomAttribute<DataMemberAttribute>() != null);
    }

    // ------- The rest of these methods are not needed -------
    public object GetCustomDataToExport(Type clrType, Type dataContractType)
    {
        throw new NotImplementedException();
    }

    public object GetCustomDataToExport(MemberInfo memberInfo, Type dataContractType)
    {
        throw new NotImplementedException();
    }

    public void GetKnownCustomDataTypes(System.Collections.ObjectModel.Collection<Type> customDataTypes)
    {
        throw new NotImplementedException();
    }

    public Type GetReferencedTypeOnImport(string typeName, string typeNamespace, object customData)
    {
        throw new NotImplementedException();
    }

    public System.CodeDom.CodeTypeDeclaration ProcessImportedType(System.CodeDom.CodeTypeDeclaration typeDeclaration, System.CodeDom.CodeCompileUnit compileUnit)
    {
        throw new NotImplementedException();
    }
}

要使用代理项，您需要创建 DataContractJsonSerializerSettings 的实例并将其传递给具有以下属性集的 DataContractJsonSerializer。请注意，由于我们需要 UseSimpleDictionaryFormat 设置，因此此解决方案仅适用于 .Net 4.5 或更高版本。

var settings = new DataContractJsonSerializerSettings();
settings.DataContractSurrogate = new MyDataContractSurrogate();
settings.KnownTypes = new List<Type> { typeof(Dictionary<string, Dictionary<string, object>>) };
settings.UseSimpleDictionaryFormat = true;

请注意，在您的 Thing class 中，您不应使用 [DataMember] 属性标记 ThingName 成员，因为它在代理中进行了特殊处理。此外，我假设您的 class 成员实际上是 properties（带有 { get; set; }），而不是像您这样的 fields在你的问题中写道。如果该假设不正确，您需要将代理代码中对 PropertyInfo 的所有引用更改为使用 FieldInfo；否则代理将无法工作。

[DataContract]
public class Thing
{
    // Don't mark this property with [DataMember]
    public string ThingName { get; set; }

    [DataMember(Name = "property1")]
    public int Property1 { get; set; }

    [DataMember(Name = "property2")]
    public string Property2 { get; set; }
}

这是一个往返演示：

public class Program
{
    public static void Main(string[] args)
    {
        string json = @"
        {
          ""thing_name1"": {
            ""property1"": 0,
            ""property2"": ""sure""
          },
          ""thing_name2"": {
            ""property1"": 34,
            ""property2"": ""absolutely""
          }
        }";

        var settings = new DataContractJsonSerializerSettings();
        settings.DataContractSurrogate = new MyDataContractSurrogate();
        settings.KnownTypes = new List<Type> { typeof(Dictionary<string, Dictionary<string, object>>) };
        settings.UseSimpleDictionaryFormat = true;

        List<Thing> things = Deserialize<List<Thing>>(json, settings);

        foreach (Thing thing in things)
        {
            Console.WriteLine("ThingName: " + thing.ThingName);
            Console.WriteLine("Property1: " + thing.Property1);
            Console.WriteLine("Property2: " + thing.Property2);
            Console.WriteLine();
        }

        json = Serialize(things, settings);
        Console.WriteLine(json);
    }

    public static T Deserialize<T>(string json, DataContractJsonSerializerSettings settings)
    {
        using (MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(json)))
        {
            var ser = new DataContractJsonSerializer(typeof(T), settings);
            return (T)ser.ReadObject(ms);
        }
    }

    public static string Serialize(object obj, DataContractJsonSerializerSettings settings)
    {
        using (MemoryStream ms = new MemoryStream())
        {
            var ser = new DataContractJsonSerializer(obj.GetType(), settings);
            ser.WriteObject(ms, obj);
            return Encoding.UTF8.GetString(ms.ToArray());
        }
    }
}

输出：

ThingName: thing_name1
Property1: 0
Property2: sure

ThingName: thing_name2
Property1: 34
Property2: absolutely

{"thing_name1":{"property1":0,"property2":"sure"},"thing_name2":{"property1":34,"property2":"absolutely"}}

是否可以使用 .NET DataContractJSONSerializer 反序列化格式不同于通常序列化的 JSON 文件？

Is it possible to use the .NET DataContractJSONSerializer to deserialize a JSON file formatted differently than it would usually serialize?

c#

json

datacontractjsonserializer