Sonar:如何使用 try-with-resources 关闭 FileOutputStream
Sonar: How to use try-with-resources to close FileOutputStream
Sonar 给出了一个错误,要求关闭此 FileOutputStream
。我需要修改以下代码才能使用 try-with-resources
。我该怎么做?
public void archivingTheFile(String zipFile){
byte[] buffer = new byte[1024];
try{
FileOutputStream fos = new FileOutputStream(zipFile);
ZipOutputStream zos = new ZipOutputStream(fos);
for(String file : this.fileList){
ZipEntry ze= new ZipEntry(file);
zos.putNextEntry(ze);
FileInputStream in = new FileInputStream(SOURCE_FOLDER + File.separator + file);
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
in.close();
}
zos.closeEntry();
zos.close();
}catch(IOException ex){
LOGGER.error("Exception occurred while zipping file",ex);
}
}
当前代码尚未准备好处理异常 - 您缺少 finally 块来关闭打开的流。而且,当然,你是对的 - 使用 try-with-resources 解决了这个问题:
public void archivingTheFile(String zipFile) {
byte[] buffer = new byte[1024];
try (FileOutputStream fos = new FileOutputStream(zipFile);
ZipOutputStream zos = new ZipOutputStream(fos)) {
for(String file : this.fileList) {
try (FileInputStream in = new FileInputStream(SOURCE_FOLDER + File.separator + file)) {
ZipEntry ze = new ZipEntry(file);
zos.putNextEntry(ze);
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
}
}
} catch(IOException ex) {
LOGGER.error("Exception occurred while zipping file",ex);
}
}
Sonar 给出了一个错误,要求关闭此 FileOutputStream
。我需要修改以下代码才能使用 try-with-resources
。我该怎么做?
public void archivingTheFile(String zipFile){
byte[] buffer = new byte[1024];
try{
FileOutputStream fos = new FileOutputStream(zipFile);
ZipOutputStream zos = new ZipOutputStream(fos);
for(String file : this.fileList){
ZipEntry ze= new ZipEntry(file);
zos.putNextEntry(ze);
FileInputStream in = new FileInputStream(SOURCE_FOLDER + File.separator + file);
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
in.close();
}
zos.closeEntry();
zos.close();
}catch(IOException ex){
LOGGER.error("Exception occurred while zipping file",ex);
}
}
当前代码尚未准备好处理异常 - 您缺少 finally 块来关闭打开的流。而且,当然,你是对的 - 使用 try-with-resources 解决了这个问题:
public void archivingTheFile(String zipFile) {
byte[] buffer = new byte[1024];
try (FileOutputStream fos = new FileOutputStream(zipFile);
ZipOutputStream zos = new ZipOutputStream(fos)) {
for(String file : this.fileList) {
try (FileInputStream in = new FileInputStream(SOURCE_FOLDER + File.separator + file)) {
ZipEntry ze = new ZipEntry(file);
zos.putNextEntry(ze);
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
}
}
} catch(IOException ex) {
LOGGER.error("Exception occurred while zipping file",ex);
}
}