UITextFieldDelegate 的 shouldChangeCharactersIn 方法 - 为什么不能组合条件语句来检查小数点分隔符和字母的数量

UITextFieldDelegate's shouldChangeCharactersIn method - why cannot combine conditional statements checking both # of decimal separators and letters

为什么我的 replacementTextHasLetter 常量不能阻止我使用以下条件将字母粘贴到我的文本字段中?

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

    let existingTextHasDecimalSeparator = textField.text?.range(of: ".")
    let replacementTextHasDecimalSeparator = string.range(of: ".")

    let charactersNotAllowed = NSCharacterSet.letters
    let replacementTextHasLetter = string.rangeOfCharacter(from: charactersNotAllowed)

    if existingTextHasDecimalSeparator != nil && replacementTextHasDecimalSeparator != nil && replacementTextHasLetter != nil {

        return false

    }

    return true

}

但是当它有自己独立的条件时它会起作用吗?

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

    let existingTextHasDecimalSeparator = textField.text?.range(of: ".")
    let replacementTextHasDecimalSeparator = string.range(of: ".")

    let charactersNotAllowed = NSCharacterSet.letters
    let replacementTextHasLetter = string.rangeOfCharacter(from: charactersNotAllowed)

    if existingTextHasDecimalSeparator != nil && replacementTextHasDecimalSeparator != nil {

        return false

    }

    if replacementTextHasLetter != nil {

        return false

    }

    return true

}

编辑:我明白了。第一个示例不可能工作,因为 existingTextHasDecimalSeparator & replacementTextHasDecimalSeparator 基本上确定文本字段中是否有小数以及用户是否试图输入一个新的,return false。当我添加

&& replacementTextHasLetter != nil

就条件而言,它并没有真正起到作用,因为所有陈述不可能同时为真。谢谢@sonofabeach

这两行:

if existingTextHasDecimalSeparator != nil && replacementTextHasDecimalSeparator != nil {
    return false
}

if replacementTextHasLetter != nil {
    return false
}

实际上与以下内容相同:

if (existingTextHasDecimalSeparator != nil && replacementTextHasDecimalSeparator != nil) || replacementTextHasLetter != nil {
    return false
}

请注意在最后一个条件中使用 || 而不是 &&