自定义 NSUserNotification 对象
Custom NSUserNotifictation object
我正在尝试修改 NSUserNotification 以传递自定义变量:
@interface MyUserNotification: NSUserNotification
@property (nonatomic) int theid;
@property (nonatomic) NSString* url;
@end
@implementation MyUserNotification
@end
然后在我的 AppDelegate
对象中启动时:
MyUserNotification *notification = [[MyUserNotification alloc] init];
notification.theid = theid;
设置theid
抛出错误:
-[_NSConcreteUserNotification setTheid:]: unrecognized selector sent to instance 0x100204840
为什么 NSConcreteUserNotification
对象参与其中?
所以这个 class 看起来并不意味着被覆盖,但好消息:有一个 userInfo 字典?
因此您可以将任何对象作为 KV 对存储在 userInfo 字典中...
int theid;
NSUserNotification *notification = [[NSUserNotification alloc] init];
NSDictionary * userInfo = [NSMutableDictionary dictionary];
[userInfo setValue:@(theid) forKey:@"theid"];
notification.userInfo = userInfo;
我正在尝试修改 NSUserNotification 以传递自定义变量:
@interface MyUserNotification: NSUserNotification
@property (nonatomic) int theid;
@property (nonatomic) NSString* url;
@end
@implementation MyUserNotification
@end
然后在我的 AppDelegate
对象中启动时:
MyUserNotification *notification = [[MyUserNotification alloc] init];
notification.theid = theid;
设置theid
抛出错误:
-[_NSConcreteUserNotification setTheid:]: unrecognized selector sent to instance 0x100204840
为什么 NSConcreteUserNotification
对象参与其中?
所以这个 class 看起来并不意味着被覆盖,但好消息:有一个 userInfo 字典?
因此您可以将任何对象作为 KV 对存储在 userInfo 字典中...
int theid;
NSUserNotification *notification = [[NSUserNotification alloc] init];
NSDictionary * userInfo = [NSMutableDictionary dictionary];
[userInfo setValue:@(theid) forKey:@"theid"];
notification.userInfo = userInfo;