Apache Phoenix Create 语句为 select（来自）

Question

我正在尝试从 Phoenix 的现有结构创建一个新的 table。 Phoenix 中是否有 CREATE as Select 语句。我正在尝试，但他们失败了，出现以下异常。

欢迎在这里提出任何建议。提前致谢。

 CREATE TABLE TEST AS (SELECT * FROM TEST_2 WHERE 1 =2);

org.apache.phoenix.exception.PhoenixParserException: ERROR 601 (42P00): Syntax error. Encountered "AS" at line 1, column 14.
        at org.apache.phoenix.exception.PhoenixParserException.newException(PhoenixParserException.java:33)
        at org.apache.phoenix.parse.SQLParser.parseStatement(SQLParser.java:111)
        at org.apache.phoenix.jdbc.PhoenixStatement$PhoenixStatementParser.parseStatement(PhoenixStatement.java:1280)
        at org.apache.phoenix.jdbc.PhoenixStatement.parseStatement(PhoenixStatement.java:1363)
        at org.apache.phoenix.jdbc.PhoenixStatement.execute(PhoenixStatement.java:1434)
        at sqlline.Commands.execute(Commands.java:822)
        at sqlline.Commands.sql(Commands.java:732)
        at sqlline.SqlLine.dispatch(SqlLine.java:808)
        at sqlline.SqlLine.begin(SqlLine.java:681)
        at sqlline.SqlLine.start(SqlLine.java:398)
        at sqlline.SqlLine.main(SqlLine.java:292)
Caused by: NoViableAltException(11@[])
        at org.apache.phoenix.parse.PhoenixSQLParser.from_table_name(PhoenixSQLParser.java:9564)
        at org.apache.phoenix.parse.PhoenixSQLParser.create_table_node(PhoenixSQLParser.java:1096)
        at org.apache.phoenix.parse.PhoenixSQLParser.oneStatement(PhoenixSQLParser.java:816)
        at org.apache.phoenix.parse.PhoenixSQLParser.statement(PhoenixSQLParser.java:508)
        at org.apache.phoenix.parse.SQLParser.parseStatement(SQLParser.java:108)
        ... 9 more
CREATE TEST  (SELECT * FROM TEST_2 WHERE 1=2);
org.apache.phoenix.exception.PhoenixParserException: ERROR 601 (42P00): Syntax error. Encountered "SELECT" at line 1, column 34.
        at org.apache.phoenix.exception.PhoenixParserException.newException(PhoenixParserException.java:33)
        at org.apache.phoenix.parse.SQLParser.parseStatement(SQLParser.java:111)
        at org.apache.phoenix.jdbc.PhoenixStatement$PhoenixStatementParser.parseStatement(PhoenixStatement.java:1280)
        at org.apache.phoenix.jdbc.PhoenixStatement.parseStatement(PhoenixStatement.java:1363)
        at org.apache.phoenix.jdbc.PhoenixStatement.execute(PhoenixStatement.java:1434)
        at sqlline.Commands.execute(Commands.java:822)
        at sqlline.Commands.sql(Commands.java:732)
        at sqlline.SqlLine.dispatch(SqlLine.java:808)
        at sqlline.SqlLine.begin(SqlLine.java:681)
        at sqlline.SqlLine.start(SqlLine.java:398)
        at sqlline.SqlLine.main(SqlLine.java:292)
Caused by: NoViableAltException(133@[])
        at org.apache.phoenix.parse.PhoenixSQLParser.column_name(PhoenixSQLParser.java:2553)
        at org.apache.phoenix.parse.PhoenixSQLParser.column_def(PhoenixSQLParser.java:3934)
        at org.apache.phoenix.parse.PhoenixSQLParser.column_defs(PhoenixSQLParser.java:3858)
        at org.apache.phoenix.parse.PhoenixSQLParser.create_table_node(PhoenixSQLParser.java:1104)
        at org.apache.phoenix.parse.PhoenixSQLParser.oneStatement(PhoenixSQLParser.java:816)
        at org.apache.phoenix.parse.PhoenixSQLParser.statement(PhoenixSQLParser.java:508)
        at org.apache.phoenix.parse.SQLParser.parseStatement(SQLParser.java:108)

Answer 1

你不能在Phoenix中这样做。

相反，您需要先创建 现有 Hbase/Phoenix table 的视图是'test_2'

所以你可以这样做：

CREATE VIEW test_view (a VARCHAR, b VARCHAR) AS
SELECT * FROM test_2
WHERE 1 = 2 ;  // some condition

有关更多信息，请参阅此处：Phoenix

Apache Phoenix Create 语句为 select（来自）

Apache Phoenix Create statement as select (from)

hbase

phoenix