在 Ruby 中创建稍微可读的单词
Creating somewhat readable words in Ruby
我正在尝试在 ruby 中创建一些可读的单词，其中包含大写字母、小写字母、数字和一个特殊字符，例如：
FlAshmnger!2
Derfing
要在 ruby 中创建一个随机字符串，您可以这样做：
lower = ('a'...'z').to_a
upper = ('A'...'Z').to_a
numbers = (0...9).to_a
specs = %w(! ? * ^ $)
size = 8
charset = [lower, upper, numbers, specs].flatten
(0...size).map { charset[rand(charset.size)] }.join
#<= ?!VVQUjH
#<= ^tsm^Led
有什么方法可以确保随机字符串具有一定的可读性？包含一个常数，元音等。具有特殊字符和至少一个数字而不使用外部 gem?
使用 .. 而不是 ... 稍微更正您的范围，这包括每个范围中的最后一个元素：
lower = ('a'..'z').to_a
upper = ('A'..'Z').to_a
numbers = (0..9).to_a
specs = %w(! ? * ^ $)
charset = [lower, upper, numbers, specs]
然后说如果你想从每个字符集中说两个，你可以这样使用Enumerable#inject：
charset.inject([]) { |memo,obj| memo + obj.sample(2) }.shuffle.join
#=> "Lf5^$O2u"
更多自定义内容：
def rand_string (l,u,n,s)
(('a'..'z').to_a.sample(l) +
('A'..'Z').to_a.sample(u) +
(0..9).to_a.sample(n) +
%w(! ? * ^ $).sample(s)).shuffle.join
end
那么一个包含 3 个小写字母、3 个大写字母、3 个数字和 1 个特殊字符的加权随机字符串为：
rand_string(3,3,3,1)
#=> "ic!I04OEr7"
从头开始创建密码
以此gist为基础:
class PasswordGenerator
# Original version : https://gist.github.com/lpar/1031933
# Simple generation of readable random passwords using Ruby
# by lpar
# These are the koremutake syllables, plus the most common 2 and 3 letter
# syllables taken from the most common 5,000 words in English, minus a few
# syllables removed so that combinations cannot generate common rude
# words in English.
SYLLABLES = %w(ba be bi bo bu by da de di do du dy fe fi fo fu fy ga ge gi
go gu gy ha he hi ho hu hy ja je ji jo ju jy ka ke ko ku ky la le li lo
lu ly ma me mi mo mu my na ne ni no nu ny pa pe pi po pu py ra re ri ro
ru ry sa se si so su sy ta te ti to tu ty va ve vi vo vu vy bra bre bri
bro bru bry dra dre dri dro dru dry fra fre fri fro fru fry gra gre gri
gro gru gry pra pre pri pro pru pry sta ste sti sto stu sty tra tre er
ed in ex al en an ad or at ca ap el ci an et it ob of af au cy im op co
up ing con ter com per ble der cal man est for mer col ful get low son
tle day pen pre ten tor ver ber can ple fer gen den mag sub sur men min
out tal but cit cle cov dif ern eve hap ket nal sup ted tem tin tro tro)
def initialize
srand
end
def generate(length)
result = ''
while result.length < length
syl = SYLLABLES[rand(SYLLABLES.length)]
result += syl
end
result = result[0,length]
# Stick in a symbol
spos = rand(length)
result[spos,1] = %w(! ? * ^ $).sample
# Stick in a digit, possibly over the symbol
dpos = rand(length)
result[dpos,1] = rand(9).to_s
# Make a letter capitalized
cpos = rand(length)
result[cpos,1] = result[cpos,1].swapcase
return result
end
end
pwgen = PasswordGenerator.new
10.times do
puts pwgen.generate(10)
end
输出示例：
Mageveur
Pehu5ima^r
a!hub8osta
b5gobrY^er
miN!e3inyf
manb1ufr^p
d^m0ndeRca
Ter5esur$b
m8r$omYket
gyso5it^le
使用 pwgen
您也可以只安装 pwgen 并使用 :
%x(pwgen).chomp
#=> "aipeebie"
对于更复杂的密码：
%x(pwgen --symbols --numerals --capitalize #{length}).chomp
#=> "Ma[Foh1EeX"
正确的马电池主食
根据这部XKCD漫画的推荐，您可以从字典中挑出4个常用词（例如/usr/share/dict/american-english）。
我正在尝试在 ruby 中创建一些可读的单词，其中包含大写字母、小写字母、数字和一个特殊字符，例如：
FlAshmnger!2
Derfing
要在 ruby 中创建一个随机字符串，您可以这样做：
lower = ('a'...'z').to_a
upper = ('A'...'Z').to_a
numbers = (0...9).to_a
specs = %w(! ? * ^ $)
size = 8
charset = [lower, upper, numbers, specs].flatten
(0...size).map { charset[rand(charset.size)] }.join
#<= ?!VVQUjH
#<= ^tsm^Led
有什么方法可以确保随机字符串具有一定的可读性？包含一个常数，元音等。具有特殊字符和至少一个数字而不使用外部 gem?
使用 .. 而不是 ... 稍微更正您的范围，这包括每个范围中的最后一个元素：
lower = ('a'..'z').to_a
upper = ('A'..'Z').to_a
numbers = (0..9).to_a
specs = %w(! ? * ^ $)
charset = [lower, upper, numbers, specs]
然后说如果你想从每个字符集中说两个，你可以这样使用Enumerable#inject：
charset.inject([]) { |memo,obj| memo + obj.sample(2) }.shuffle.join
#=> "Lf5^$O2u"
更多自定义内容：
def rand_string (l,u,n,s)
(('a'..'z').to_a.sample(l) +
('A'..'Z').to_a.sample(u) +
(0..9).to_a.sample(n) +
%w(! ? * ^ $).sample(s)).shuffle.join
end
那么一个包含 3 个小写字母、3 个大写字母、3 个数字和 1 个特殊字符的加权随机字符串为：
rand_string(3,3,3,1)
#=> "ic!I04OEr7"
从头开始创建密码
以此gist为基础:
class PasswordGenerator
# Original version : https://gist.github.com/lpar/1031933
# Simple generation of readable random passwords using Ruby
# by lpar
# These are the koremutake syllables, plus the most common 2 and 3 letter
# syllables taken from the most common 5,000 words in English, minus a few
# syllables removed so that combinations cannot generate common rude
# words in English.
SYLLABLES = %w(ba be bi bo bu by da de di do du dy fe fi fo fu fy ga ge gi
go gu gy ha he hi ho hu hy ja je ji jo ju jy ka ke ko ku ky la le li lo
lu ly ma me mi mo mu my na ne ni no nu ny pa pe pi po pu py ra re ri ro
ru ry sa se si so su sy ta te ti to tu ty va ve vi vo vu vy bra bre bri
bro bru bry dra dre dri dro dru dry fra fre fri fro fru fry gra gre gri
gro gru gry pra pre pri pro pru pry sta ste sti sto stu sty tra tre er
ed in ex al en an ad or at ca ap el ci an et it ob of af au cy im op co
up ing con ter com per ble der cal man est for mer col ful get low son
tle day pen pre ten tor ver ber can ple fer gen den mag sub sur men min
out tal but cit cle cov dif ern eve hap ket nal sup ted tem tin tro tro)
def initialize
srand
end
def generate(length)
result = ''
while result.length < length
syl = SYLLABLES[rand(SYLLABLES.length)]
result += syl
end
result = result[0,length]
# Stick in a symbol
spos = rand(length)
result[spos,1] = %w(! ? * ^ $).sample
# Stick in a digit, possibly over the symbol
dpos = rand(length)
result[dpos,1] = rand(9).to_s
# Make a letter capitalized
cpos = rand(length)
result[cpos,1] = result[cpos,1].swapcase
return result
end
end
pwgen = PasswordGenerator.new
10.times do
puts pwgen.generate(10)
end
输出示例：
Mageveur
Pehu5ima^r
a!hub8osta
b5gobrY^er
miN!e3inyf
manb1ufr^p
d^m0ndeRca
Ter5esur$b
m8r$omYket
gyso5it^le
使用 pwgen
您也可以只安装 pwgen 并使用 :
%x(pwgen).chomp
#=> "aipeebie"
对于更复杂的密码：
%x(pwgen --symbols --numerals --capitalize #{length}).chomp
#=> "Ma[Foh1EeX"
正确的马电池主食
根据这部XKCD漫画的推荐，您可以从字典中挑出4个常用词（例如/usr/share/dict/american-english）。