如何从 Web API 2 HttpGet 发送 zip 文件
How to send a zip file from Web API 2 HttpGet
我正在尝试弄清楚如何从给定的文件夹路径创建新的 zip 文件,并将其发送回发件人。
需要的是文件将下载到请求它的发件人处。
我看过很多答案,但 none 帮我找到了准确的答案。
我的代码:
Guid folderGuid = Guid.NewGuid();
string folderToZip = ConfigurationManager.AppSettings["folderToZip"] + folderGuid.ToString();
Directory.CreateDirectory(folderToZip);
string directoryPath = ConfigurationManager.AppSettings["DirectoryPath"];
字符串 combinedPath = Path.Combine(directoryPath, id);
DirectoryInfo di = new DirectoryInfo(combinedPath);
如果(di.Exists)
{
//提供要创建的 zip 文件的路径和名称
字符串 zipFile = folderToZip + "\" + folderGuid + ".zip";
//call the ZipFile.CreateFromDirectory() method
ZipFile.CreateFromDirectory(combinedPath, zipFile, CompressionLevel.Fastest, true);
var result = new HttpResponseMessage(HttpStatusCode.OK);
using (ZipArchive zip = ZipFile.Open(zipFile, ZipArchiveMode.Read))
{
zip.CreateEntryFromFile(folderFiles, "file.zip");
}
var stream = new FileStream(zipFile, FileMode.Open);
result.Content = new StreamContent(stream);
result.Content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
result.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
{
FileName = "file.zip"
};
log.Debug("END ExportFiles()");
return ResponseMessage(result);
在你的控制器中:
using System.IO.Compression.FileSystem; // Reference System.IO.Compression.FileSystem.dll
[HttpGet]
[Route("api/myzipfile"]
public dynamic DownloadZip([FromUri]string dirPath)
{
if(!System.IO.Directory.Exists(dirPath))
return this.NotFound();
var tempFile = System.IO.Path.Combine(System.IO.Path.GetTempPath(), Guid.NewGuid()); // might want to clean this up if there are a lot of downloads
ZipFile.CreateFromDirectory(dirPath, tempFile);
HttpResponseMessage response = new HttpResponseMessage(HttpStatusCode.OK);
response.Content = new StreamContent(new FileStream(tempFile, FileMode.Open, FileAccess.Read));
response.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment");
response.Content.Headers.ContentDisposition.FileName = fileName;
response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/zip");
return response;
}
UPD:文件已存在的解决方法
我正在尝试弄清楚如何从给定的文件夹路径创建新的 zip 文件,并将其发送回发件人。
需要的是文件将下载到请求它的发件人处。 我看过很多答案,但 none 帮我找到了准确的答案。
我的代码:
Guid folderGuid = Guid.NewGuid(); string folderToZip = ConfigurationManager.AppSettings["folderToZip"] + folderGuid.ToString();
Directory.CreateDirectory(folderToZip);
string directoryPath = ConfigurationManager.AppSettings["DirectoryPath"]; 字符串 combinedPath = Path.Combine(directoryPath, id);
DirectoryInfo di = new DirectoryInfo(combinedPath); 如果(di.Exists) { //提供要创建的 zip 文件的路径和名称 字符串 zipFile = folderToZip + "\" + folderGuid + ".zip";
//call the ZipFile.CreateFromDirectory() method
ZipFile.CreateFromDirectory(combinedPath, zipFile, CompressionLevel.Fastest, true);
var result = new HttpResponseMessage(HttpStatusCode.OK);
using (ZipArchive zip = ZipFile.Open(zipFile, ZipArchiveMode.Read))
{
zip.CreateEntryFromFile(folderFiles, "file.zip");
}
var stream = new FileStream(zipFile, FileMode.Open);
result.Content = new StreamContent(stream);
result.Content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
result.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
{
FileName = "file.zip"
};
log.Debug("END ExportFiles()");
return ResponseMessage(result);
在你的控制器中:
using System.IO.Compression.FileSystem; // Reference System.IO.Compression.FileSystem.dll
[HttpGet]
[Route("api/myzipfile"]
public dynamic DownloadZip([FromUri]string dirPath)
{
if(!System.IO.Directory.Exists(dirPath))
return this.NotFound();
var tempFile = System.IO.Path.Combine(System.IO.Path.GetTempPath(), Guid.NewGuid()); // might want to clean this up if there are a lot of downloads
ZipFile.CreateFromDirectory(dirPath, tempFile);
HttpResponseMessage response = new HttpResponseMessage(HttpStatusCode.OK);
response.Content = new StreamContent(new FileStream(tempFile, FileMode.Open, FileAccess.Read));
response.Content.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("attachment");
response.Content.Headers.ContentDisposition.FileName = fileName;
response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/zip");
return response;
}
UPD:文件已存在的解决方法