将分层数据转换为平面数据 table
Transform hierarchical data into flat table
我正在使用 ms sql.
研究分层数据（作为 概括工作订单 的解决方案）
*
I am open to design change on my initial table and/or to add other
tables.
*
这是我的数据
ID ParentID Type Value
38 0 Num 327
39 38 Sector 21
40 38 Sector 22
43 40 Product NS
44 40 Product MS
50 40 Temp RAS
48 44 Quantity 60
47 43 Quantity 25
41 39 Product ARF
42 39 Product BRF
49 39 Temp RAS
51 39 Cible Acarien A.
46 42 Quantity 30
52 42 Cible Acarien B.
45 41 Quantity 20
我想将其转换为：
Num Sector Product Quantity
327 21 ARF 20
327 21 BRF 30
327 22 NS 25
327 22 MS 60
[使用 Gurwinder 的回答的结果]
num sector product quantity
327 22 MS 60
327 22 NS 25
327 21 BRF 30
327 21 BRF Acarien B.
327 21 ARF 20
[顺吾的做法]
<root>
<row Num="327" Sector="s2" Temp="normal" />
<row Num="327" Sector="s2" Product="BRF" Qte="70" />
<row Num="327" Sector="s2" Product="ARF" Qte="45" />
<row Num="327" Sector="s1" Temp="normal" />
<row Num="327" Sector="s1" Cible="Acarien a." />
<row Num="327" Sector="s1" Product="NS" Qte="35" />
<row Num="327" Sector="s1" Product="NS" Cible="Acarien b." />
<row Num="327" Sector="s1" Product="MS" Qte="60" />
</root>
非常感谢你们的宝贵时间。
select t1.value num,
t2.value sector,
t3.value product,
t4.value quantity
from table t1
inner join table t2
on t1.id = t2.parentid
and t1.parentid = 0
inner join table t3
on t2.id = t3.parentid
inner join table t4
on t3.id = t4.parentid;
这个技巧怎么样？
DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(10),Value VARCHAR(10))
INSERT INTO @tbl VALUES
(1,0,'Num','327')
,(2,1,'Sector','21')
,(3,1,'Sector','22')
,(4,2,'Product','ARF')
,(5,2,'Product','BRF')
,(6,3,'Product','NS')
,(7,3,'Product','MS')
,(8,4,'Quantity','20')
,(9,5,'Quantity','30')
,(10,6,'Quantity','25')
,(11,7,'Quantity','60');
WITH recCTE AS
(
SELECT *,0 AS HLevel,Type + N'="' + CAST(Value AS NVARCHAR(MAX)) + N'" ' AS attr
FROM @tbl WHERE ParentID=0
UNION ALL
SELECT t.*,r.HLevel+1,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
FROM @tbl AS t
INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr + N'/>' AS XML)
FROM recCTE
WHERE HLevel=3
FOR XML PATH(''),ROOT('root')
结果
<root>
<row Num="327" Sector="22" Product="MS" Quantity="60" />
<row Num="327" Sector="22" Product="NS" Quantity="25" />
<row Num="327" Sector="21" Product="BRF" Quantity="30" />
<row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>
这个XML很容易查询... 最深层次（这里我取了HLevel=3）一般都可以找到——但是你需要提供更多详细信息...
更新
如果一个节点是叶节点
，下面将不会使用给定的深度作为过滤器，而是使用查询来检查
我在最后加了一行
DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(100),Value VARCHAR(100))
INSERT INTO @tbl VALUES
(1,0,'Num','327')
,(2,1,'Sector','21')
,(3,1,'Sector','22')
,(4,2,'Product','ARF')
,(5,2,'Product','BRF')
,(6,3,'Product','NS')
,(7,3,'Product','MS')
,(8,4,'Quantity','20')
,(9,5,'Quantity','30')
,(10,6,'Quantity','25')
,(11,7,'Quantity','60')
,(13,11,'SomeMore','Test as fourth');
WITH recCTE AS
(
SELECT t.*
,0 AS HLevel
,t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" ' AS attr
,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
FROM @tbl AS t WHERE ParentID=0
UNION ALL
SELECT t.*
,r.HLevel+1
,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
FROM @tbl AS t
INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr + N'/>' AS XML)
FROM recCTE
WHERE IsLeaf=1
FOR XML PATH(''),ROOT('root')
结果
<root>
<row Num="327" Sector="22" Product="MS" Quantity="60" SomeMore="Test as fourth" />
<row Num="327" Sector="22" Product="NS" Quantity="25" />
<row Num="327" Sector="21" Product="BRF" Quantity="30" />
<row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>
更新 2：使用您的真实数据
正如您已经发现的那样，您的问题一团糟...不知道您真正需要什么，但是如果我 运行 通过此查询获得您的真实数据，我会得到这个:
DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(100),Value VARCHAR(100))
INSERT INTO @tbl VALUES
(38,0,'Num','327')
,(39,38,'Sector','21')
,(40,38,'Sector','22')
,(43,40,'Product','NS')
,(44,40,'Product','MS')
,(50,40,'Temp','RAS')
,(48,44,'Quantity','60')
,(47,43,'Quantity','25')
,(41,39,'Product','ARF')
,(42,39,'Product','BRF')
,(49,39,'Temp','RAS')
,(51,39,'Cible','Acarien A.')
,(46,42,'Quantity','30')
,(52,42,'Cible','Acarien B.')
,(45,41,'Quantity','20');
WITH recCTE AS
(
SELECT t.*
,0 AS HLevel
,t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" ' AS attr
,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
FROM @tbl AS t WHERE ParentID=0
UNION ALL
SELECT t.*
,r.HLevel+1
,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
FROM @tbl AS t
INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr + N'/>' AS XML)
FROM recCTE
WHERE IsLeaf=1
FOR XML PATH(''),ROOT('root')
结果
<root>
<row Num="327" Sector="22" Temp="RAS" />
<row Num="327" Sector="22" Product="MS" Quantity="60" />
<row Num="327" Sector="22" Product="NS" Quantity="25" />
<row Num="327" Sector="21" Temp="RAS" />
<row Num="327" Sector="21" Cible="Acarien A." />
<row Num="327" Sector="21" Product="BRF" Quantity="30" />
<row Num="327" Sector="21" Product="BRF" Cible="Acarien B." />
<row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>
我正在使用 ms sql.
研究分层数据（作为 概括工作订单 的解决方案）*
I am open to design change on my initial table and/or to add other tables.
*
这是我的数据
ID ParentID Type Value
38 0 Num 327
39 38 Sector 21
40 38 Sector 22
43 40 Product NS
44 40 Product MS
50 40 Temp RAS
48 44 Quantity 60
47 43 Quantity 25
41 39 Product ARF
42 39 Product BRF
49 39 Temp RAS
51 39 Cible Acarien A.
46 42 Quantity 30
52 42 Cible Acarien B.
45 41 Quantity 20
我想将其转换为：
Num Sector Product Quantity
327 21 ARF 20
327 21 BRF 30
327 22 NS 25
327 22 MS 60
[使用 Gurwinder 的回答的结果]
num sector product quantity
327 22 MS 60
327 22 NS 25
327 21 BRF 30
327 21 BRF Acarien B.
327 21 ARF 20
[顺吾的做法]
<root>
<row Num="327" Sector="s2" Temp="normal" />
<row Num="327" Sector="s2" Product="BRF" Qte="70" />
<row Num="327" Sector="s2" Product="ARF" Qte="45" />
<row Num="327" Sector="s1" Temp="normal" />
<row Num="327" Sector="s1" Cible="Acarien a." />
<row Num="327" Sector="s1" Product="NS" Qte="35" />
<row Num="327" Sector="s1" Product="NS" Cible="Acarien b." />
<row Num="327" Sector="s1" Product="MS" Qte="60" />
</root>
非常感谢你们的宝贵时间。
select t1.value num,
t2.value sector,
t3.value product,
t4.value quantity
from table t1
inner join table t2
on t1.id = t2.parentid
and t1.parentid = 0
inner join table t3
on t2.id = t3.parentid
inner join table t4
on t3.id = t4.parentid;
这个技巧怎么样？
DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(10),Value VARCHAR(10))
INSERT INTO @tbl VALUES
(1,0,'Num','327')
,(2,1,'Sector','21')
,(3,1,'Sector','22')
,(4,2,'Product','ARF')
,(5,2,'Product','BRF')
,(6,3,'Product','NS')
,(7,3,'Product','MS')
,(8,4,'Quantity','20')
,(9,5,'Quantity','30')
,(10,6,'Quantity','25')
,(11,7,'Quantity','60');
WITH recCTE AS
(
SELECT *,0 AS HLevel,Type + N'="' + CAST(Value AS NVARCHAR(MAX)) + N'" ' AS attr
FROM @tbl WHERE ParentID=0
UNION ALL
SELECT t.*,r.HLevel+1,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
FROM @tbl AS t
INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr + N'/>' AS XML)
FROM recCTE
WHERE HLevel=3
FOR XML PATH(''),ROOT('root')
结果
<root>
<row Num="327" Sector="22" Product="MS" Quantity="60" />
<row Num="327" Sector="22" Product="NS" Quantity="25" />
<row Num="327" Sector="21" Product="BRF" Quantity="30" />
<row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>
这个XML很容易查询... 最深层次（这里我取了HLevel=3）一般都可以找到——但是你需要提供更多详细信息...
更新
如果一个节点是叶节点
，下面将不会使用给定的深度作为过滤器，而是使用查询来检查我在最后加了一行
DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(100),Value VARCHAR(100))
INSERT INTO @tbl VALUES
(1,0,'Num','327')
,(2,1,'Sector','21')
,(3,1,'Sector','22')
,(4,2,'Product','ARF')
,(5,2,'Product','BRF')
,(6,3,'Product','NS')
,(7,3,'Product','MS')
,(8,4,'Quantity','20')
,(9,5,'Quantity','30')
,(10,6,'Quantity','25')
,(11,7,'Quantity','60')
,(13,11,'SomeMore','Test as fourth');
WITH recCTE AS
(
SELECT t.*
,0 AS HLevel
,t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" ' AS attr
,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
FROM @tbl AS t WHERE ParentID=0
UNION ALL
SELECT t.*
,r.HLevel+1
,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
FROM @tbl AS t
INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr + N'/>' AS XML)
FROM recCTE
WHERE IsLeaf=1
FOR XML PATH(''),ROOT('root')
结果
<root>
<row Num="327" Sector="22" Product="MS" Quantity="60" SomeMore="Test as fourth" />
<row Num="327" Sector="22" Product="NS" Quantity="25" />
<row Num="327" Sector="21" Product="BRF" Quantity="30" />
<row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>
更新 2：使用您的真实数据
正如您已经发现的那样，您的问题一团糟...不知道您真正需要什么，但是如果我 运行 通过此查询获得您的真实数据，我会得到这个:
DECLARE @tbl TABLE(ID INT,ParentID INT,Type VARCHAR(100),Value VARCHAR(100))
INSERT INTO @tbl VALUES
(38,0,'Num','327')
,(39,38,'Sector','21')
,(40,38,'Sector','22')
,(43,40,'Product','NS')
,(44,40,'Product','MS')
,(50,40,'Temp','RAS')
,(48,44,'Quantity','60')
,(47,43,'Quantity','25')
,(41,39,'Product','ARF')
,(42,39,'Product','BRF')
,(49,39,'Temp','RAS')
,(51,39,'Cible','Acarien A.')
,(46,42,'Quantity','30')
,(52,42,'Cible','Acarien B.')
,(45,41,'Quantity','20');
WITH recCTE AS
(
SELECT t.*
,0 AS HLevel
,t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" ' AS attr
,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
FROM @tbl AS t WHERE ParentID=0
UNION ALL
SELECT t.*
,r.HLevel+1
,attr+t.Type + N'="' + CAST(t.Value AS NVARCHAR(MAX)) + N'" '
,CASE WHEN EXISTS(SELECT 1 FROM @tbl AS x WHERE x.ParentID=t.ID) THEN 0 ELSE 1 END AS IsLeaf
FROM @tbl AS t
INNER JOIN recCTE AS r ON t.ParentID=r.ID
)
SELECT CAST(N'<row ' + attr + N'/>' AS XML)
FROM recCTE
WHERE IsLeaf=1
FOR XML PATH(''),ROOT('root')
结果
<root>
<row Num="327" Sector="22" Temp="RAS" />
<row Num="327" Sector="22" Product="MS" Quantity="60" />
<row Num="327" Sector="22" Product="NS" Quantity="25" />
<row Num="327" Sector="21" Temp="RAS" />
<row Num="327" Sector="21" Cible="Acarien A." />
<row Num="327" Sector="21" Product="BRF" Quantity="30" />
<row Num="327" Sector="21" Product="BRF" Cible="Acarien B." />
<row Num="327" Sector="21" Product="ARF" Quantity="20" />
</root>