获取所有子文件夹的列表

Question

我有一个程序逻辑问题，如何获取服务器上所有文件夹的列表：

比方说，我有一个如下所示的文件夹结构，我想获取其中所有文件夹的列表：

![在此处输入图片描述][1]

String rootDirectory = “Root”; 
CmdClient client = null; 
client.connect("demo.asperasoft.com", "asperaweb", "demoaspera", 22);

// This method gives list of files inside param folder CmdReplyFile cmdfiles=client.execLs(rootDirectory);

//this method gives a list of files 
File[] fileObjects = cmdfiles.getFileList();

//this method gives file count 
int fileCount= cmdfiles.getFileCount();

这里的文件Class不是Java文件class。现在，当我尝试打印所有文件夹的列表时，它只是给我：

阿尔法测试版伽马

private void getFolderList(String rootDirectory) throws IOException, CmdClientException {
        CmdReplyFile cmdfiles=client.execLs(rootDirectory);
        File[] fileObjects = cmdfiles.getFileList();
        for (File fileObject : fileObjects) {
            if (fileObject.isDirectory()) {
                System.out.println(fileObject.getName());
                getFolderList(fileObject.getName());
            }
        }

请提出一个可能的逻辑。

Answer 1

我希望下面的代码能满足您的要求：

public void getListOfFolders(String rootPath) {
    List<String> folders = new LinkedList<String>();
    getFolders(rootPath, folders);
    // Now folders got everything you need.
}

public void getFolders(String directoryName, List<String> folders) {
    File directory = new File(directoryName);
    File[] fList = directory.listFiles();
    for (File file : fList) {
        if (file.isDirectory()) {
            folders.add(file.getAbsolutePath());
            getFolders(file.getAbsolutePath(), folders);
        }
    }
}

Answer 2

谢谢卡提克！我能够使用您的解决方案做到这一点：

public void getListOfFolders(String rootPath) throws IOException, CmdClientException {
    List<String> folders = new LinkedList<String>();
    folders.add(rootPath);
    getFolders(rootPath, folders);

    for (String items : folders){
        System.out.println("Folders: "+items.toString());
    }
}

public void getFolders(String directoryName, List<String> folders) throws IOException, CmdClientException {
    CmdReplyFile cmdfiles=client.execLs(directoryName);
    File[] fileObjects = cmdfiles.getFileList();
    String dirStructure=folders.get(folders.size()-1).toString();
    for (File file : fileObjects) {
        if (file.isDirectory()) {
            String folderPath=dirStructure+file.getName()+"/";
            folders.add(folderPath);
            getFolders(folderPath, folders);
        }
    }
}

获取所有子文件夹的列表

Get list of all subfolders

java

algorithm

recursion

logic

functional-programming