Alloy：一个紧凑的 Java 程序，用于执行不同的 运行 命令范围
Alloy: a compact Java program to perform different run command scopes
假设我想创建一个 Java 程序来执行多个 Alloy 运行，为每个循环更改它们的范围值（从 0 到 9 的整数），以检查哪个将要运行找到一个花费更少时间的解决方案。
请注意，命令实际上是相同的，我的意思是，只有范围的值（以及保留字“exactly”的 presence/absence）会有所不同。
这是一个数字示例：
1st run → command: run MyPred for 3 but 5 Int, exactly 1 Sig_Scope1, 1 Sig_Scope2, exactly 1 Sig_Scope3
2nd run → command: run MyPred for 4 but 5 Int, 2 Sig_Scope1, exactly 2 Sig_Scope2, exactly 2 Sig_Scope3
3rd run → command: run MyPred for 4 but 5 Int, 2 Sig_Scope1, exactly 1 Sig_Scope2, 1 Sig_Scope3
以此类推，直到达到最大迭代次数（假设为10）。
10th run → command: run MyPred for 4 but 5 Int, 0 Sig_Scope1, exactly 2 Sig_Scope2, 0 Sig_Scope3
程序输出将是这样的：
1st run. Found solution: Yes. Spent time: 17 seconds
2nd run. Found solution: No. Spent time: [it may take a time until the Alloy analyzer is going to return no solution]
3nd run. Found solution: No. Spent time: [it may take a time until the Alloy analyzer is going to return no solution]
...
9th run. Found solution: Yes. Spent time: 21 seconds
10th run. Found solution: Yes. Spent time: 10 seconds
这是我正在尝试通过的伪代码，但是有很多部分（文本问题）我不知道如何实现它或如何找到更多研究material:
...
A4Reporter rep = new A4Reporter() {...}
...
Module world = CompUtil.parseEverything_fromFile(rep, null, filename); //reading Alloy filename.
...
A4Options options = new A4Options(); //Analyzer’s options.
...
Command command: world.getAllCommands(); //I’am looking for Alloy’s ‘run’ commands, for instance, the first run command would be: run MyPred for 3 but 3 Int, exactly 1 Sig_Scope1, 1 Sig_Scope2, exactly 1 Sig_Scope3
...
Int max_number_of_runs = 10;
for(i = 0; i < max_number_of_runs; i++) {
A4Solution ans = TranslateAlloyToKodkod.execute_command(rep, world.getAllReachableSigs(), command, options); //get all Signatures, fine :)
System.out.println(ans); //printing the whole command.
if (ans.satisfiable()) {
//How can I get the amount of time (in seconds) to found a solution as an integer or String?
//Getting the label of the Sigs. I have got this way, however I do not know if it is the right one.
SafeList<Sig> sigs = ans.getAllReachableSigs();
for (Sig sig : sigs) {
System.out.println(sig.shortLabel());
}
//For each Sig how can I get their values?
//How can I build a new command (Command new_built_command) for the next run? The values of scope Sig will come from a list or they will be generated through Java Random class (I mean a know how to generate random integers).
command = new_built_command;
} else {
//A message that the current command did not find a solution as a String!
}
}
你能帮我解决一下吗？
How can I build a new command
可以看到ExampleUsingTheAPI for an example of using the Alloy API for constructing Alloy models. Using that API you can programmatically construct a Command to run. Alternatively, you can start with an Alloy model in a text form, parse it using CompUtil.parseEverything_fromString，然后在原来的Alloy模型上做一个字符串查找替换更新命令，从头再来
For each Sig how can I get their values?
参见 ExampleCompilingFromSource，第 44 行。基本上，一旦获得 A4Solution 对象，就可以对其调用 eval 方法来根据找到的解决方案评估任何表达式（如果你传递一个 Sig 对象，你将在解决方案中获得它的值。
How can I get the amount of time (in seconds) to found a solution as an integer or String?
我不确定 A4Solution 是否包含任何有关解决时间的信息，因此在那种情况下，您必须自己测量时间。
假设我想创建一个 Java 程序来执行多个 Alloy 运行，为每个循环更改它们的范围值（从 0 到 9 的整数），以检查哪个将要运行找到一个花费更少时间的解决方案。
请注意，命令实际上是相同的，我的意思是，只有范围的值（以及保留字“exactly”的 presence/absence）会有所不同。
这是一个数字示例：
1st run → command: run MyPred for 3 but 5 Int, exactly 1 Sig_Scope1, 1 Sig_Scope2, exactly 1 Sig_Scope3
2nd run → command: run MyPred for 4 but 5 Int, 2 Sig_Scope1, exactly 2 Sig_Scope2, exactly 2 Sig_Scope3
3rd run → command: run MyPred for 4 but 5 Int, 2 Sig_Scope1, exactly 1 Sig_Scope2, 1 Sig_Scope3
以此类推，直到达到最大迭代次数（假设为10）。
10th run → command: run MyPred for 4 but 5 Int, 0 Sig_Scope1, exactly 2 Sig_Scope2, 0 Sig_Scope3
程序输出将是这样的：
1st run. Found solution: Yes. Spent time: 17 seconds
2nd run. Found solution: No. Spent time: [it may take a time until the Alloy analyzer is going to return no solution]
3nd run. Found solution: No. Spent time: [it may take a time until the Alloy analyzer is going to return no solution]
...
9th run. Found solution: Yes. Spent time: 21 seconds
10th run. Found solution: Yes. Spent time: 10 seconds
这是我正在尝试通过的伪代码，但是有很多部分（文本问题）我不知道如何实现它或如何找到更多研究material:
...
A4Reporter rep = new A4Reporter() {...}
...
Module world = CompUtil.parseEverything_fromFile(rep, null, filename); //reading Alloy filename.
...
A4Options options = new A4Options(); //Analyzer’s options.
...
Command command: world.getAllCommands(); //I’am looking for Alloy’s ‘run’ commands, for instance, the first run command would be: run MyPred for 3 but 3 Int, exactly 1 Sig_Scope1, 1 Sig_Scope2, exactly 1 Sig_Scope3
...
Int max_number_of_runs = 10;
for(i = 0; i < max_number_of_runs; i++) {
A4Solution ans = TranslateAlloyToKodkod.execute_command(rep, world.getAllReachableSigs(), command, options); //get all Signatures, fine :)
System.out.println(ans); //printing the whole command.
if (ans.satisfiable()) {
//How can I get the amount of time (in seconds) to found a solution as an integer or String?
//Getting the label of the Sigs. I have got this way, however I do not know if it is the right one.
SafeList<Sig> sigs = ans.getAllReachableSigs();
for (Sig sig : sigs) {
System.out.println(sig.shortLabel());
}
//For each Sig how can I get their values?
//How can I build a new command (Command new_built_command) for the next run? The values of scope Sig will come from a list or they will be generated through Java Random class (I mean a know how to generate random integers).
command = new_built_command;
} else {
//A message that the current command did not find a solution as a String!
}
}
你能帮我解决一下吗？
How can I build a new command
可以看到ExampleUsingTheAPI for an example of using the Alloy API for constructing Alloy models. Using that API you can programmatically construct a Command to run. Alternatively, you can start with an Alloy model in a text form, parse it using CompUtil.parseEverything_fromString，然后在原来的Alloy模型上做一个字符串查找替换更新命令，从头再来
For each Sig how can I get their values?
参见 ExampleCompilingFromSource，第 44 行。基本上，一旦获得 A4Solution 对象，就可以对其调用 eval 方法来根据找到的解决方案评估任何表达式（如果你传递一个 Sig 对象，你将在解决方案中获得它的值。
How can I get the amount of time (in seconds) to found a solution as an integer or String?
我不确定 A4Solution 是否包含任何有关解决时间的信息，因此在那种情况下，您必须自己测量时间。