如何使用 mysql 查询获取 parent_id?
How to get parent_id using mysql query?
如果我的 SQL 查询是这样的:
SELECT * FROM master_lookups WHERE `type` = 'fungsi'`,
那么结果是这样的:
(图片 1)
如果我的 SQL 查询是这样的:
SELECT @rownum := @rownum + 1 AS id,
NULL AS parent_id,
kdsfungsi AS `code`,
nmsfungsi AS `name`,
'sub_fungsi' AS `type`,
CONCAT('{"kdfungsi":"', kdfungsi, '"}') AS information
FROM dblaplakgar.t_sfungsi
CROSS JOIN (SELECT @rownum := 735) r
那么结果是这样的:
(图 2)
我要图2的结果,存在值parent_id。字段parent_id的值取自图1中的id,基于字段kdfungsi.
所以对于图2中的值parent_id,结果是这样的:
- id 736,其父id:735
- id 737,其父id:735
- id 738,其父id:734
获得 parent_id 后,我使用此查询插入:
INSERT INTO master_lookups (id,parent_id,`code`,`name`,`type`,information)
SELECT @rownum := @rownum + 1 AS id,
NULL AS parent_id,
kdsfungsi AS `code`,
nmsfungsi AS `name`,
'sub_fungsi' AS `type`,
CONCAT('{"kdfungsi":"', kdfungsi, '"}') AS information
FROM dblaplakgar.t_sfungsi
CROSS JOIN (SELECT @rownum := 735) r
有 parent_id 个值仍然为 NULL。
我需要根据图 1 中显示的字段 kdfungsi 填写图 2 中的 parent_id。
我该怎么做?
要从 master_lookups table 中获取 id 值,您可以这样做:
SELECT @rownum := @rownum + 1 AS id,
m.id AS parent_id,
t.kdsfungsi AS `code`,
t.nmsfungsi AS `name`,
'sub_fungsi' AS `type`,
CONCAT('{"kdfungsi":"', t.kdfungsi, '"}') AS information
FROM dblaplakgar.t_sfungsi t
LEFT JOIN master_lookups m
ON m.type = 'fungsi'
AND m.code = t.kdfungsi
CROSS JOIN (SELECT @rownum := 735) r
如果我的 SQL 查询是这样的:
SELECT * FROM master_lookups WHERE `type` = 'fungsi'`,
那么结果是这样的:
(图片 1)
如果我的 SQL 查询是这样的:
SELECT @rownum := @rownum + 1 AS id,
NULL AS parent_id,
kdsfungsi AS `code`,
nmsfungsi AS `name`,
'sub_fungsi' AS `type`,
CONCAT('{"kdfungsi":"', kdfungsi, '"}') AS information
FROM dblaplakgar.t_sfungsi
CROSS JOIN (SELECT @rownum := 735) r
那么结果是这样的:
(图 2)
我要图2的结果,存在值parent_id。字段parent_id的值取自图1中的id,基于字段kdfungsi.
所以对于图2中的值parent_id,结果是这样的:
- id 736,其父id:735
- id 737,其父id:735
- id 738,其父id:734
获得 parent_id 后,我使用此查询插入:
INSERT INTO master_lookups (id,parent_id,`code`,`name`,`type`,information)
SELECT @rownum := @rownum + 1 AS id,
NULL AS parent_id,
kdsfungsi AS `code`,
nmsfungsi AS `name`,
'sub_fungsi' AS `type`,
CONCAT('{"kdfungsi":"', kdfungsi, '"}') AS information
FROM dblaplakgar.t_sfungsi
CROSS JOIN (SELECT @rownum := 735) r
有 parent_id 个值仍然为 NULL。
我需要根据图 1 中显示的字段 kdfungsi 填写图 2 中的 parent_id。
我该怎么做?
要从 master_lookups table 中获取 id 值,您可以这样做:
SELECT @rownum := @rownum + 1 AS id,
m.id AS parent_id,
t.kdsfungsi AS `code`,
t.nmsfungsi AS `name`,
'sub_fungsi' AS `type`,
CONCAT('{"kdfungsi":"', t.kdfungsi, '"}') AS information
FROM dblaplakgar.t_sfungsi t
LEFT JOIN master_lookups m
ON m.type = 'fungsi'
AND m.code = t.kdfungsi
CROSS JOIN (SELECT @rownum := 735) r