将 lambda 作为参数传递给 rake 任务

Question

我正在为 bootstrap 我的 gem 项目构建一个 cli，设置 minitest、guard、travis、git 等...

我正计划使用 Rake，因为我喜欢它处理依赖项、shell 命令和清理的方式。

首先，我正在创建一个 "type" 项目的目录结构（gem、gli、美沙酮），然后渲染 erb 中的所有文件 template 项目目录。

如图所示 methadone => gem 和 gli => gem 但 methadone !=> gli。这意味着 methadone 需要 gem 中的所有文件，但可能会添加新的 files/dirs，也可能会修改现有的 files/dirs.

我喜欢用 Rake 任务表达这些依赖关系是多么容易。

但我觉得很奇怪，我必须在 3 个不同的地方编写相同的代码，如下所示：

代码：

require 'rake'
require 'rake/clean'

desc "Bootstrap gem"
task :gem, [:project_name] do |t, args|
  Project.new(t.name, args.project_name).bootstrap
end

desc "Bootstrap methadone"
task :methadone, [:project_name] => :gem do |t, args|
  Project.new(t.name, args.project_name).bootstrap
end

desc "Bootstrap gli"
task :gli, [:project_name] => :gem do |t, args|
  Project.new(t.name, args.project_name).bootstrap
end

class Project
  attr_reader :project_name, :template_name
  def initialize template_name, project_name
    @project_name = project_name
    @template_name = template_name
  end

  def bootstrap 
    create_project_dirs 
    render 
  end

  def create_project_dirs   
    puts "Copying dirs from #{template_dir} to #{project_dir}"
  end

  def render   
    puts "Rendering #{project_name} templates..."
  end

  def template_dir
    File.expand_path(File.join(__dir__, "templates", template_name))
  end

  def project_dir
    File.expand_path(File.join(__dir__, project_name))
  end
end



CLEAN.include('templates')

template_files = %w( templates/gem/foo.erb templates/gem/bar.erb templates/methadone/foo.erb templates/gli/foo.erb )
template_files.each do |f|
  file f do |t|
    path = t.name
    mkdir_p File.dirname path
    touch path
  end
end

desc "Setup tmp project"
task :setup => template_files

文件结构：

$ tree .
.
├── Rakefile
├── some.rake
└── templates
    ├── gem
    │   ├── bar.erb
    │   └── foo.erb
    ├── gli
    │   └── foo.erb
    └── methadone
        └── foo.erb

4 directories, 6 files

是否可以在调用它的任务上下文中创建一个 Rake 任务运行并获取参数？

然后我想我可以有这样的任务：

desc "Bootstrap gem"
task :gem, [:project_name] => :bootstrap ??

desc "Bootstrap methadone"
task :methadone, [:project_name] => [:gem, :bootstrap]

desc "Bootstrap gli"
task :gli, [:project_name] =>[:gem, :bootstrap]

task :bootstrap ??
  Project.new(t.name, args.project_name).bootstrap
end

输出：

$ rake methadone['some_gem']
Copying dirs from /Users/max/Dropbox/work/tmp/devify_dependency/templates/gem to /Users/max/Dropbox/work/tmp/devify_dependency/some_gem
Rendering some_gem templates...
Copying dirs from /Users/max/Dropbox/work/tmp/devify_dependency/templates/methadone to /Users/max/Dropbox/work/tmp/devify_dependency/some_gem
Rendering some_gem templates...

但目前我不知道如何告诉 :bootstrap 调用它的任务或如何将调用它的任务的参数传递给它。

Answer 1

如果我正确理解你想要实现的目标，有一个非常简单的重构：

BOOTSTRAP = lambda do |t, args|
  Project.new(t.name, args.project_name).bootstrap
end

desc "Bootstrap gem"
task :gem, [:project_name], &BOOTSTRAP

desc "Bootstrap methadone"
task :methadone, [:project_name], &BOOTSTRAP

desc "Bootstrap gli"
task :gli, [:project_name] => :gem, &BOOTSTRAP

将 lambda 作为参数传递给 rake 任务

Pass lambda as an argument to rake task

ruby

rake