为什么在此 GraphQL 设置中未调用 DataFetcher?
Why is DataFetcher not called in this GraphQL setup?
我想写一段代码来处理像这样的 GraphQL 查询:
query {
group(id: "com.graphql-java")
name(name: "graphql-java")
version(id: "2.3.0")
}
我创建了一个数据获取器并在 get
方法中放置了一个断点:
import graphql.schema.DataFetcher;
import graphql.schema.DataFetchingEnvironment;
public class TestDataFetcher implements DataFetcher {
public Object get(final DataFetchingEnvironment dataFetchingEnvironment) {
return null;
}
}
然后我写了下面的代码:
public class Example02 {
public static void main(final String[] args) throws IOException {
final Example02 app = new Example02();
app.run();
}
void run() throws IOException {
final TestDataFetcher testDataFetcher = new TestDataFetcher();
final List<GraphQLFieldDefinition> fields = Lists.newArrayList(
createGroupField(testDataFetcher),
createNameField(),
createVersionField());
final GraphQLObjectType queryType = newObject()
.name("query")
.fields(fields)
.build();
final GraphQLSchema schema = GraphQLSchema.newSchema()
.query(queryType)
.build();
final String query = FileUtils.readFileToString(
new File("src/main/resources/query1.txt"),
"UTF-8"
);
final Map<String, Object> result = (Map<String, Object>) new GraphQL(schema).execute(query).getData();
System.out.println(result);
}
private GraphQLFieldDefinition createVersionField() {
return newFieldDefinition().type(GraphQLString).name("version").build();
}
private GraphQLFieldDefinition createNameField() {
return newFieldDefinition().type(GraphQLString).name("name").build();
}
private GraphQLFieldDefinition createGroupField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition()
.type(GraphQLString)
.name("group")
.dataFetcher(testDataFetcher)
.argument(idArg)
.build();
}
}
当我在debug模式下运行方法main
时,断点没有激活
为什么?我该如何解决?
你的问题是你的查询。如果调试变量 query
,它是 query {\n group(id: "com.graphql-java")\n name(name: "graphql-java")\n version(id: "2.3.0")\n}
。
问题是查询中的“\n”。
如果您将查询更改为 query{group(id: "com.graphql-java")}
您的断点将被执行。
要执行您的查询,我必须先更新 GraphQlFiledDefinitions 以接收参数。
private GraphQLFieldDefinition createVersionField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition().type(GraphQLString).name("version").staticValue("id value").argument(idArg).build();
}
private GraphQLFieldDefinition createNameField(TestDataFetcher testDataFetcher) {
final GraphQLArgument nameArg = newArgument().name("name").type(GraphQLString).build();
return newFieldDefinition().type(GraphQLString).name("name").staticValue("name Value").argument(nameArg).build();
}
private GraphQLFieldDefinition createGroupField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition()
.type(GraphQLString)
.name("group")
.dataFetcher(testDataFetcher)
.argument(idArg)
.build();
}
然后我可以使用没有换行符的查询query {group(id: "com.graphql-java"),name(name:"graphql-java"),version(id: "2.3.0")}
这是您的工作示例。
我已经使用了您发布的查询文件。
根据需要进一步实施您的 dataFetcher。
基本上您应该已经定义了名称和版本字段的参数。
当你 运行 new GraphQL(schema).execute(query)
时,调试器会告诉你一切
它有 errors
个包含所有问题的数组。
import graphql.GraphQL;
import graphql.schema.*;
import org.apache.commons.io.FileUtils;
import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import static graphql.Scalars.GraphQLString;
import static graphql.schema.GraphQLArgument.newArgument;
import static graphql.schema.GraphQLFieldDefinition.newFieldDefinition;
import static graphql.schema.GraphQLObjectType.newObject;
public class Example2 {
public class TestDataFetcher implements DataFetcher {
public Object get(DataFetchingEnvironment environment) {
String id = (String)environment.getArgument("id");
return id;
}
}
public static void main(final String[] args) {
Example2 app = new Example2();
app.run();
}
void run() {
TestDataFetcher testDataFetcher = new TestDataFetcher();
List<GraphQLFieldDefinition> fields = new ArrayList<GraphQLFieldDefinition>();
fields.add(createGroupField(testDataFetcher));
fields.add(createNameField());
fields.add(createVersionField());
GraphQLObjectType queryType = newObject()
.name("query")
.fields(fields)
.build();
GraphQLSchema schema = GraphQLSchema.newSchema()
.query(queryType)
.build();
String query = null;
try {
query = FileUtils.readFileToString(
new File("src/main/resources/query1.txt"),
"UTF-8"
);
}catch(IOException ioe){
ioe.printStackTrace();
}
if(query!=null) {
Map<String, Object> result = (Map<String, Object>) new GraphQL(schema).execute(query).getData();
System.out.println(result);
}
}
private GraphQLFieldDefinition createVersionField() {
GraphQLArgument arg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition().type(GraphQLString).name("version").argument(arg).build();
}
private GraphQLFieldDefinition createNameField() {
GraphQLArgument arg = newArgument().name("name").type(GraphQLString).build();
return newFieldDefinition().type(GraphQLString).name("name").argument(arg).build();
}
private GraphQLFieldDefinition createGroupField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition()
.type(GraphQLString)
.name("group")
.dataFetcher(testDataFetcher)
.argument(idArg)
.build();
}
}
我想写一段代码来处理像这样的 GraphQL 查询:
query {
group(id: "com.graphql-java")
name(name: "graphql-java")
version(id: "2.3.0")
}
我创建了一个数据获取器并在 get
方法中放置了一个断点:
import graphql.schema.DataFetcher;
import graphql.schema.DataFetchingEnvironment;
public class TestDataFetcher implements DataFetcher {
public Object get(final DataFetchingEnvironment dataFetchingEnvironment) {
return null;
}
}
然后我写了下面的代码:
public class Example02 {
public static void main(final String[] args) throws IOException {
final Example02 app = new Example02();
app.run();
}
void run() throws IOException {
final TestDataFetcher testDataFetcher = new TestDataFetcher();
final List<GraphQLFieldDefinition> fields = Lists.newArrayList(
createGroupField(testDataFetcher),
createNameField(),
createVersionField());
final GraphQLObjectType queryType = newObject()
.name("query")
.fields(fields)
.build();
final GraphQLSchema schema = GraphQLSchema.newSchema()
.query(queryType)
.build();
final String query = FileUtils.readFileToString(
new File("src/main/resources/query1.txt"),
"UTF-8"
);
final Map<String, Object> result = (Map<String, Object>) new GraphQL(schema).execute(query).getData();
System.out.println(result);
}
private GraphQLFieldDefinition createVersionField() {
return newFieldDefinition().type(GraphQLString).name("version").build();
}
private GraphQLFieldDefinition createNameField() {
return newFieldDefinition().type(GraphQLString).name("name").build();
}
private GraphQLFieldDefinition createGroupField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition()
.type(GraphQLString)
.name("group")
.dataFetcher(testDataFetcher)
.argument(idArg)
.build();
}
}
当我在debug模式下运行方法main
时,断点没有激活
为什么?我该如何解决?
你的问题是你的查询。如果调试变量 query
,它是 query {\n group(id: "com.graphql-java")\n name(name: "graphql-java")\n version(id: "2.3.0")\n}
。
问题是查询中的“\n”。
如果您将查询更改为 query{group(id: "com.graphql-java")}
您的断点将被执行。
要执行您的查询,我必须先更新 GraphQlFiledDefinitions 以接收参数。
private GraphQLFieldDefinition createVersionField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition().type(GraphQLString).name("version").staticValue("id value").argument(idArg).build();
}
private GraphQLFieldDefinition createNameField(TestDataFetcher testDataFetcher) {
final GraphQLArgument nameArg = newArgument().name("name").type(GraphQLString).build();
return newFieldDefinition().type(GraphQLString).name("name").staticValue("name Value").argument(nameArg).build();
}
private GraphQLFieldDefinition createGroupField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition()
.type(GraphQLString)
.name("group")
.dataFetcher(testDataFetcher)
.argument(idArg)
.build();
}
然后我可以使用没有换行符的查询query {group(id: "com.graphql-java"),name(name:"graphql-java"),version(id: "2.3.0")}
这是您的工作示例。
我已经使用了您发布的查询文件。
根据需要进一步实施您的 dataFetcher。
基本上您应该已经定义了名称和版本字段的参数。
当你 运行 new GraphQL(schema).execute(query)
时,调试器会告诉你一切
它有 errors
个包含所有问题的数组。
import graphql.GraphQL;
import graphql.schema.*;
import org.apache.commons.io.FileUtils;
import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import static graphql.Scalars.GraphQLString;
import static graphql.schema.GraphQLArgument.newArgument;
import static graphql.schema.GraphQLFieldDefinition.newFieldDefinition;
import static graphql.schema.GraphQLObjectType.newObject;
public class Example2 {
public class TestDataFetcher implements DataFetcher {
public Object get(DataFetchingEnvironment environment) {
String id = (String)environment.getArgument("id");
return id;
}
}
public static void main(final String[] args) {
Example2 app = new Example2();
app.run();
}
void run() {
TestDataFetcher testDataFetcher = new TestDataFetcher();
List<GraphQLFieldDefinition> fields = new ArrayList<GraphQLFieldDefinition>();
fields.add(createGroupField(testDataFetcher));
fields.add(createNameField());
fields.add(createVersionField());
GraphQLObjectType queryType = newObject()
.name("query")
.fields(fields)
.build();
GraphQLSchema schema = GraphQLSchema.newSchema()
.query(queryType)
.build();
String query = null;
try {
query = FileUtils.readFileToString(
new File("src/main/resources/query1.txt"),
"UTF-8"
);
}catch(IOException ioe){
ioe.printStackTrace();
}
if(query!=null) {
Map<String, Object> result = (Map<String, Object>) new GraphQL(schema).execute(query).getData();
System.out.println(result);
}
}
private GraphQLFieldDefinition createVersionField() {
GraphQLArgument arg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition().type(GraphQLString).name("version").argument(arg).build();
}
private GraphQLFieldDefinition createNameField() {
GraphQLArgument arg = newArgument().name("name").type(GraphQLString).build();
return newFieldDefinition().type(GraphQLString).name("name").argument(arg).build();
}
private GraphQLFieldDefinition createGroupField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition()
.type(GraphQLString)
.name("group")
.dataFetcher(testDataFetcher)
.argument(idArg)
.build();
}
}