android - 时间递减倒计时
android - countdown with decreasing time
在我的游戏中,用户在 5 秒内单击按钮时会得到一分。现在我希望计时器减少用户获得的每一点的时间 - 例如零分时,用户有五秒的时间,而当他有一分时,他只有 4.5 秒的时间再次点击它并获得第二分。我用for循环解决吗?
public class GameScreen extends Activity {
public int score = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_game);
Button count = (Button) findViewById(R.id.button1);
text = (TextView) this.findViewById(R.id.textView3);
tvscore = (TextView) findViewById(R.id.score);
timer();
}
public void gameover() {
Intent intent = new Intent(this, GameOverScreen.class);
startActivity(intent);
}
public void onClick (View view) {
score++;
tvscore.setText(String.valueOf(score));
timer();
}
public void timer(){
new CountDownTimer(5000, 10) {
public void onTick(long millisUntilFinished) {
text.setText(""+String.format("%02d:%03d",
TimeUnit.MILLISECONDS.toSeconds(millisUntilFinished) - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millisUntilFinished)),
TimeUnit.MILLISECONDS.toMillis(millisUntilFinished) - TimeUnit.SECONDS.toMillis(TimeUnit.MILLISECONDS.toSeconds(millisUntilFinished))
));
if(animationRunning) {
cancel();
}
}
public void onFinish() {
text.setText("Too slow.");
gameover();
}
}.start();
}
}
这样做怎么样:
public void timer(float time) {
new CountDownTimer(time, 10) {
// YOUR CODE
}
}
public void onClick (View view) {
score++;
tvscore.setText(String.valueOf(score));
timer(Math.max(5000-score*500, 2000));
}
我想每次点击(分数)都会减少 500 毫秒的时间...
Limit - Math.max(a, b)
会选择最大值。意思是当5000-score*500
低于2000时,它会选择2000毫秒代替
只有定时器方法:
public void timer() {
float time = Math.max(5000-score*500, 2000)
new CountDownTimer(time, 10) {
// YOUR CODE
}
}
在我的游戏中,用户在 5 秒内单击按钮时会得到一分。现在我希望计时器减少用户获得的每一点的时间 - 例如零分时,用户有五秒的时间,而当他有一分时,他只有 4.5 秒的时间再次点击它并获得第二分。我用for循环解决吗?
public class GameScreen extends Activity {
public int score = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_game);
Button count = (Button) findViewById(R.id.button1);
text = (TextView) this.findViewById(R.id.textView3);
tvscore = (TextView) findViewById(R.id.score);
timer();
}
public void gameover() {
Intent intent = new Intent(this, GameOverScreen.class);
startActivity(intent);
}
public void onClick (View view) {
score++;
tvscore.setText(String.valueOf(score));
timer();
}
public void timer(){
new CountDownTimer(5000, 10) {
public void onTick(long millisUntilFinished) {
text.setText(""+String.format("%02d:%03d",
TimeUnit.MILLISECONDS.toSeconds(millisUntilFinished) - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millisUntilFinished)),
TimeUnit.MILLISECONDS.toMillis(millisUntilFinished) - TimeUnit.SECONDS.toMillis(TimeUnit.MILLISECONDS.toSeconds(millisUntilFinished))
));
if(animationRunning) {
cancel();
}
}
public void onFinish() {
text.setText("Too slow.");
gameover();
}
}.start();
}
}
这样做怎么样:
public void timer(float time) {
new CountDownTimer(time, 10) {
// YOUR CODE
}
}
public void onClick (View view) {
score++;
tvscore.setText(String.valueOf(score));
timer(Math.max(5000-score*500, 2000));
}
我想每次点击(分数)都会减少 500 毫秒的时间...
Limit - Math.max(a, b)
会选择最大值。意思是当5000-score*500
低于2000时,它会选择2000毫秒代替
只有定时器方法:
public void timer() {
float time = Math.max(5000-score*500, 2000)
new CountDownTimer(time, 10) {
// YOUR CODE
}
}