在vhdl中制作一个算术逻辑单元

Make an arithmetic logic unit in vhdl

我需要用 VHDL 为 pic16f684 制作一个算术逻辑单元。 因此,可以在 pic16f684 的数据表中找到 ALU 的说明。

我需要做的说明如下:

These are the instructions

到目前为止,这是我的代码,但我得到了一个 std_logic_vector 不能在向量中包含字符的错误,这很符合逻辑,但我不知道该怎么做换个方式..

LIBRARY IEEE;
USE  IEEE.STD_LOGIC_1164.all;
USE  IEEE.STD_LOGIC_ARITH.all;
USE  IEEE.STD_LOGIC_UNSIGNED.all;

ENTITY AluPIC IS

   PORT(    -- Input Signals    
        Op_code     : in std_logic_vector(6 DOWNTO 0);
        win, fin        : in std_logic_vector(7 DOWNTO 0);
         -- Output Signals
        d,z : out std_logic;
        ALU_output  : out std_logic_vector(7 DOWNTO 0));


END AluPIC;

ARCHITECTURE behavior OF AluPIC IS
        -- declare signal(s) internal to module here
SIGNAL temp_output,wout,fout: std_logic_vector(7 DOWNTO 0);

BEGIN
  PROCESS (Op_code, win, fin)
    BEGIN
        -- Select Arithmetic/Logical Operation
    CASE Op_Code (6 DOWNTO 0) IS
        WHEN "000111d" =>
            if d ='0' then
                wout <= win + fin;
                temp_output <=wout;
            else
                fout <= win + fin;
                temp_output <= fout;
            end if;

        WHEN "000101d" =>
            if d ='0' then
                wout <= win and fin;
                temp_output <= wout;
            else
                fout <= win and fin;
                temp_output <= fout;
            end if;

        WHEN "000001l" =>
             fout <= fin;
             fout <= "00000000";
             z <= '1';
             temp_output <= fout;

        WHEN "001010d" =>
            fout <= fin+1;
             if d = '0' then
                wout <= fout;
                temp_output <=wout;
             else
                fout <= fout;
                temp_output <=fout;
            end if;

        WHEN "001000d" =>
        if d = '0' then
            wout  <= fin;
            temp_output <= wout;
            z <= '1';
        else
            fout <= fin;
            temp_output <= fout;
            z <= '1';
        end if;

        WHEN "0101bbb" =>
            fout <= fin;
             temp_output <= fout;
        WHEN OTHERS =>
            temp_output <= "00000000";
    END CASE;
            -- Select Shift Operation
    IF Op_Code(0) = '1' THEN
            -- Shift bits left with zero fill using concatination operator
            -- can also use VHDL 1076-1993 shift operator such as SLL 
        Alu_output <= temp_output(6 DOWNTO 0) & '0';
    ELSE 
        Alu_output <= temp_output;
    END IF;
  END PROCESS;
END behavior;

谢谢你们抽出时间!

WHEN "000111d" =>WHEN "0101bbb" => 等行无效,因为您的 case 语句使用 std_logic_vector,但 "000111d" 是一个字符串。

不清楚您要用 db 字符实现什么,但是您的各种 when 行应该与有效的 std_logic_vector正确的长度,例如 WHEN "0000111" =>.

查看您的操作代码图像,它显示 table,其中包含包含操作的行,例如 'ADDWF'。在这些操作中,只有最高有效的 6 位似乎 select 操作,最低有效位被标记为 bd。这个最低有效位实际上是操作的参数,而不是操作码的一部分。 table 没有显示 d 对操作有什么影响,但你似乎已经解决了这个问题。以 ADDWF 为例,我会像这样更改您的代码:

CASE Op_Code (6 DOWNTO 1) IS
  WHEN "000111" =>
    if Op_Code(0) ='0' then
      wout <= win + fin;
      temp_output <=wout;
    else
      fout <= win + fin;
      temp_output <= fout;
    end if;
  -- ...
end case;

'BSF' 操作是个例外,因为它使用最低有效的 3 位作为参数。您可以使用匹配的 case 语句或通过列出一种情况下的所有可能性来编写此代码:

匹配案例,需要VHDL2008:

CASE? Op_Code (6 DOWNTO 1) IS
  WHEN "0101--" =>
    -- Set a bit based on `op_code (2 downto 0)`
end case?;

列出所有可能性:

CASE Op_Code (6 DOWNTO 1) IS
  WHEN "010100" | "010101" | "010110" | "010111" =>
    -- Set a bit based on `op_code (2 downto 0)`
end case;