评论抓取表单 tripadvisor

Question

我是 python3 中网络抓取的新手。我想抓取迪拜所有酒店的评论，但问题是我只能抓取我在 url 中描述的酒店评论。谁能告诉我如何在不隐式给出每家酒店的 url 的情况下获得所有酒店评论？

import requests
from bs4 import BeautifulSoup


importurl = 'https://www.tripadvisor.com/Hotel_Review-g295424-d302778-Reviews-Roda_Al_Bustan_Dubai_Airport-Dubai_Emirate_of_Dubai.html'
r = requests.get(importurl)
soup = BeautifulSoup(r.content, "lxml")
 resultsoup = soup.find_all("p", {"class" : "partial_entry"})
#save the reviews to a test text file locally
for review in resultsoup:
review_list = review.get_text()
print(review_list)
with open('testreview.txt', 'w') as fid: 
    for review in resultsoup:
        review_list = review.get_text()
        fid.write(review_list)

Answer 1

你应该找到所有酒店的索引页，将所有 link 放入列表中，然后循环 url 列表以获取评论。

import bs4, requests
index_pages = ('http://www.tripadvisor.cn/Hotels-g295424-oa{}-Dubai_Emirate_of_Dubai-Hotels.html#ACCOM_OVERVIEW'.format(i) for i in range(0, 540, 30))
urls = []
with requests.session() as s:
    for index in index_pages:
        r = s.get(index)
        soup = bs4.BeautifulSoup(r.text, 'lxml')
        url_list = [i.get('href') for i in soup.select('.property_title')]
        urls.append(url_list)

输出：

len(urls): 540

评论抓取表单 tripadvisor

Review scraping form tripadvisor

python

python-3.x

web-scraping

beautifulsoup

tripadvisor