SQL select 将事务行转换为列

Question

我有一个 table 列出所有交易如下：

ID  Account Date    Amount
---------------------------
1   2   02/01/2015  30
2   5   05/01/2015  25
3   2   05/01/2015  12
4   2   07/01/2015  42
5   5   10/012015   19
6   2   11/01/2015  58
7   3   15/01/2015  36

想写一个 select 语句，只列出每个账户的最后 3 笔交易，如下所示。

Account Date1   Amount      Date2   Amount      Date3   Amount
---------------------------------------------------------------
2       11/01/2015  58      07/01/2015  42      05/01/2015  12
3       15/01/2015  36              
5       10/01/2015  19      05/01/2015  25

感谢您的任何建议

Answer 1

您可以在派生的 table 中使用 row_number() 函数按帐户对数据进行分区，并为分区中的每个日期指定一个数字，然后对行进行条件聚合前 3 个数字，按帐户分组：

select 
    account,
    date1  = max(case when rn = 1 then date   end),
    amount = max(case when rn = 1 then amount end),
    date2  = max(case when rn = 2 then date   end),
    amount = max(case when rn = 2 then amount end),
    date3  = max(case when rn = 3 then date   end),
    amount = max(case when rn = 3 then amount end)
from (
    select *, rn = row_number() over (partition by account order by date desc) 
    from your_table
) a
where rn <= 3
group by account

Sample SQL Fiddle

SQL select 将事务行转换为列

SQL select converting transaction rows to columns

tsql

sql-server-2008-r2

pivot

greatest-n-per-group