ReactiveCocoa - concat 展平策略未按预期工作

ReactiveCocoa - concat flatten strategy not working as expected

我这几天开始学习reactive-cocoa,今天我在玩reactivecocoa(reactiveSwift)的flatten方法,我尝试执行给定的代码片段文档 Basic operators 中的 concat 扁平化。这是片段:

let (lettersSignal, lettersObserver) = Signal<String, NoError>.pipe()
let (numbersSignal, numbersObserver) = Signal<String, NoError>.pipe()
let (signal, observer) = Signal<Signal<String, NoError>, NoError>.pipe()

signal.flatten(.concat).observeValues { print([=10=]) }

observer.send(value: lettersSignal)
observer.send(value: numbersSignal)
observer.sendCompleted()

numbersObserver.send(value: "1")    // nothing printed
lettersObserver.send(value: "a")    // prints "a"
lettersObserver.send(value: "b")    // prints "b"
numbersObserver.send(value: "2")    // nothing printed
lettersObserver.send(value: "c")    // prints "c"
lettersObserver.sendCompleted()     // prints "1, 2"
numbersObserver.send(value: "3")    // prints "3"
numbersObserver.sendCompleted()

根据文档和交互式可视化图表(RAC marbles - flatten(.concat) visual diagram,输出应该是这样的,

首先它应该打印字母流,即

a, b, c

& 一旦 letterStream 完成,它应该打印数字流,即

1, 2, 3

所以这个观察的最终输出应该是

[a, b, c, 1, 2, 3]

但是,我看到的串联输出是,

[a, b, c, 3]

为什么会这样?为什么只打印 numberStream 的最新值?而不是在字母流完成后打印整个数字流值。

如果我误解了什么,请告诉我。干杯。

ReactiveSwift's slack channel中所述,这是预期的结果。

Quoting the documentation:

The outer event stream is started observed. Each subsequent event stream is not observed until the preceeding one has completed.

所以 numbersSignal 只会在 lettersObserver 完成后发送值。