FirebaseListAdapter 字母顺序
FirebaseListAdapter alphabetical order
在我的 Android 应用程序中,我有一个带有 FirebaseListAdapter
的 ListView 向我显示我的用户,现在我希望 firebaseListAdapter 按字母顺序排序。我怎样才能做到这一点?
代码:
mListView = (ListView) findViewById(R.id.listView);
DatabaseReference databaseReference = FirebaseDatabase.getInstance().getReference().child("Users");
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference
){
@Override
protected void populateView(View v, String model, int position) {
TextView textView = (TextView) v.findViewById(android.R.id.text1);
textView.setText(model);
}
};
mListView.setAdapter(firebaseListAdapter);
这取决于名字是什么。如果您将用户存储在他们的名字下(这样名字就是键):
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference.orderByKey()
){
但是,例如,如果您将 属性 的名称称为 "name",您将使用:
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference.orderByChild("name")
){
最后:如果您想按键的单个字符串值排序:
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference.orderByValue()
){
我找到了解决方案!
这是工作代码:
mListView = (ListView) findViewById(R.id.listView);
DatabaseReference databaseReference = FirebaseDatabase.getInstance().getReference().child("Users");
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference.orderByValue()
){
@Override
protected void populateView(View v, String model, int position) {
TextView textView = (TextView) v.findViewById(android.R.id.text1);
textView.setText(model);
}
};
mListView.setAdapter(firebaseListAdapter);
在我的 Android 应用程序中,我有一个带有 FirebaseListAdapter
的 ListView 向我显示我的用户,现在我希望 firebaseListAdapter 按字母顺序排序。我怎样才能做到这一点?
代码:
mListView = (ListView) findViewById(R.id.listView);
DatabaseReference databaseReference = FirebaseDatabase.getInstance().getReference().child("Users");
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference
){
@Override
protected void populateView(View v, String model, int position) {
TextView textView = (TextView) v.findViewById(android.R.id.text1);
textView.setText(model);
}
};
mListView.setAdapter(firebaseListAdapter);
这取决于名字是什么。如果您将用户存储在他们的名字下(这样名字就是键):
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference.orderByKey()
){
但是,例如,如果您将 属性 的名称称为 "name",您将使用:
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference.orderByChild("name")
){
最后:如果您想按键的单个字符串值排序:
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference.orderByValue()
){
我找到了解决方案!
这是工作代码:
mListView = (ListView) findViewById(R.id.listView);
DatabaseReference databaseReference = FirebaseDatabase.getInstance().getReference().child("Users");
FirebaseListAdapter<String> firebaseListAdapter = new FirebaseListAdapter<String>(
this,
String.class,
android.R.layout.simple_list_item_1,
databaseReference.orderByValue()
){
@Override
protected void populateView(View v, String model, int position) {
TextView textView = (TextView) v.findViewById(android.R.id.text1);
textView.setText(model);
}
};
mListView.setAdapter(firebaseListAdapter);