在终端输出周围创建星号边框？

Question

我需要在终端中的命令输出周围创建一个边框，例如，如果命令的输出是这样的：

Apple
Paper Clip
Water

会变成这样：

/==========\
|Apple     |
|Paper Clip|
|Water     |
\==========/

提前感谢您的所有回复。
-C.L

Answer 1

awk 似乎是最不疯狂的方法：

command | expand | awk 'length([=10=]) > length(longest) { longest = [=10=] } { lines[NR] = [=10=] } END { gsub(/./, "=", longest); print "/=" longest "=\"; n = length(longest); for(i = 1; i <= NR; ++i) { printf("| %s %*s\n", lines[i], n - length(lines[i]) + 1, "|"); } print "\=" longest "=/" }'

expand 用适当数量的空格替换输出中可能出现的制表符以保持其外观相同（这是为了确保输出的每个字节都以相同的宽度呈现） . awk 代码的工作原理如下：

length([=11=]) > length(longest) {  # Remember the longest line
  longest = [=11=]
}
{                               # also remember all lines in order
  lines[NR] = [=11=]
}
END {                           # when you have everything:
  gsub(/./, "=", longest)       # build a line of = as long as the longest
                                # line
  print "/=" longest "=\"      # use it to print the top bit

  n = length(longest)           # format the content with left and right
  for(i = 1; i <= NR; ++i) {    # delimiters; spacing through printf
    printf("| %s %*s\n", lines[i], n - length(lines[i]) + 1, "|")
  }

  print "\=" longest "=/"      # print bottom bit.
}

最疯狂的方法，我敢说你对此有异议，是用 sed:

#!/bin/sed -f

# assemble lines in the hold buffer, preceded by the left delimiter
s/^/| /
1h
1!H
$!d

# make a copy of it in the pattern space
x
h

# isolate the longest line (or rather: a line of = as long as the longest
# line)
s/[^\n]/=/g
:a
/^\(=*\)\n/ {
  s///
  ba
}
//! {
  s/\n=*//
  ta
}

# build top bit, print it
s,.*,/&\,
p

# build measuring stick
s,.\(.*\).,=,

# for all lines in the output:
:lineloop

# fetch the line
G
s/^\(=*\n\)\([^\n]*\).*//

# replace it with = to get a second measuring stick
s/[^\n]/=/g

# fetch another copy of the line
G
s/^\(=*\n=*\n\)\([^\n]*\).*//

# inner loop:
:spaceloop

# while the line measuring stick is not as long as the overall measuring
# stick
/^\(=*\)\n/! {
  # append a = to it and a space to the line for output
  s/\n/\n=/
  s/$/ /
  b spaceloop
}

# once that is done, append the second delimiter
s/$/|/
# remove one measuring stick
s/=*\n//
# put the second behind the actual line
s/\(.*\)\n\(.*\)/\n/
# print the line
P
# remove it. Only the measuring stick remains and can be reused for the
# next line
s/.*\n//

# do this while there are more lines to be processed
x
/\n/ {
 s/[^\n]*\n//
 x
 b lineloop
}

# then build the bottom bit and print it.
x
s/=/\/
s/$/\//

将其放入文件 foo.sed，使用 command | expand | sed -f foo.sed。但只做一次以确认它有效。您不想运行在生产中使用类似的东西。

Answer 2

不是您要找的语言，但简洁易读：

#!/usr/bin/env ruby
input = STDIN.read.split("\n")
width = input.map(&:size).max + 2
bar = '='*(width-2)
puts '/' + bar  + '\'
input.each {|i| puts "|"+i+" "*(width-i.size-2)+"|" }
puts '\'+ bar + '/'

您可以将其保存在一个文件中，chmod +x它，然后将您的输入输入其中。

如果你"need"将它放在一行中：

echo e"Apple\nPaper Clip\nWater" | 
ruby -e 'i=STDIN.read.split("\n");w=i.map(&:size).max+2;b="="*(w-2);i.map! {|j| "|"+j+" "*(w-j.size-2)+"|" };i.unshift "/"+b+"\"; i<<"\"+b+"/";puts i'

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