检查数组的元素是否包含指定的字符串

Question

我正在开发 iOS 应用程序。我有一个数组，

NSArray *qwer=[NSArray arrayWithObjects:@"Apple Juice",@"Apple cake",@"Apple chips",@"Apple wassail"nil];
for(int k=0; k<qwer.count; k++) {
    //
}

我正在尝试检查我的数组是否包含字符串“wassail”。谁能帮我找到这个？

Answer 1

NSString 有一个 rangeOfString 函数，可用于查找部分字符串匹配。这个函数returnsNSRange。您可以使用 location 属性.

...
  NSArray *qwer = [NSArray arrayWithObjects:@"Apple Juice",@"Apple cake",@"Apple chips",@"Apple wassail"nil];
    for (NSString *name in qwer){
      if ([name rangeOfString:keyword].location == NSNotFound) {
        NSLog(@"contains");
      } 
    }
...

参考：

1. https://developer.apple.com/reference/foundation/nsstring/1416849-rangeofstring
2. https://developer.apple.com/reference/foundation/nsrange

谢谢 斯里拉姆

Answer 2

试试这个

NSArray *qwer=[NSArray arrayWithObjects:@"Apple Juice",@"Apple cake",@"Apple chips",@"Apple wassail",nil];
for(int k=0; k<qwer.count; k++) {
    NSString *currentString =[qwer objectAtIndex:k];
    if ([currentString rangeOfString:@"wassail"].location == NSNotFound) {
        NSLog(@"string does not contain wassail");
    } else {
        NSLog(@"string contains wassail!");

        break;
    }
}