如何删除 android 中光标持续时间为 0 的歌曲
How to remove songs which has 0 duration in cursor in android
我正在创建音乐应用程序。我使用光标在列表视图中显示歌曲。我不知道如何从光标中删除持续时间为 0 的歌曲。
这是我在列表视图中显示所有歌曲的代码。
public MediaCursorAdapter(Context context, int layout, Cursor c) {
super(context, layout, c,
new String[]{MediaStore.MediaColumns.DISPLAY_NAME, MediaStore.MediaColumns.TITLE, MediaStore.Audio.AudioColumns.DURATION},
new int[]{R.id.displayname, R.id.title, R.id.duration});
}
@Override
public void bindView(View view, Context context, Cursor cursor) {
TextView title = (TextView) view.findViewById(R.id.title);
TextView name = (TextView) view.findViewById(R.id.displayname);
TextView duration = (TextView) view.findViewById(R.id.duration);
long durationInMs = Long.parseLong(cursor.getString(
cursor.getColumnIndex(MediaStore.Audio.AudioColumns.DURATION)));
name.setText(cursor.getString(
cursor.getColumnIndex(MediaStore.MediaColumns.DISPLAY_NAME)));
title.setText(cursor.getString(
cursor.getColumnIndex(MediaStore.MediaColumns.TITLE)));
Duration d = new Duration();
String durationInMin = d.convertDuration(durationInMs);
duration.setText("" + durationInMin);
view.setTag(cursor.getString(cursor.getColumnIndex(MediaStore.MediaColumns.DATA)));
}
@Override
public View newView(Context context, Cursor cursor, ViewGroup parent) {
LayoutInflater inflater = LayoutInflater.from(context);
View v = inflater.inflate(R.layout.listitem, parent, false);
bindView(v, context, cursor);
return v;
}
可以通过在 contentResolver.query 方法中添加 where 子句(MediaStore.Audio.AudioColumns.DURATION+">0" 在我的代码中)来解决,如下所示:
cursor = getContentResolver().query(MediaStore.Audio.Media.EXTERNAL_CONTENT_URI, null,MediaStore.Audio.AudioColumns.DURATION+">0", null, sortOrder);
我正在创建音乐应用程序。我使用光标在列表视图中显示歌曲。我不知道如何从光标中删除持续时间为 0 的歌曲。
这是我在列表视图中显示所有歌曲的代码。
public MediaCursorAdapter(Context context, int layout, Cursor c) {
super(context, layout, c,
new String[]{MediaStore.MediaColumns.DISPLAY_NAME, MediaStore.MediaColumns.TITLE, MediaStore.Audio.AudioColumns.DURATION},
new int[]{R.id.displayname, R.id.title, R.id.duration});
}
@Override
public void bindView(View view, Context context, Cursor cursor) {
TextView title = (TextView) view.findViewById(R.id.title);
TextView name = (TextView) view.findViewById(R.id.displayname);
TextView duration = (TextView) view.findViewById(R.id.duration);
long durationInMs = Long.parseLong(cursor.getString(
cursor.getColumnIndex(MediaStore.Audio.AudioColumns.DURATION)));
name.setText(cursor.getString(
cursor.getColumnIndex(MediaStore.MediaColumns.DISPLAY_NAME)));
title.setText(cursor.getString(
cursor.getColumnIndex(MediaStore.MediaColumns.TITLE)));
Duration d = new Duration();
String durationInMin = d.convertDuration(durationInMs);
duration.setText("" + durationInMin);
view.setTag(cursor.getString(cursor.getColumnIndex(MediaStore.MediaColumns.DATA)));
}
@Override
public View newView(Context context, Cursor cursor, ViewGroup parent) {
LayoutInflater inflater = LayoutInflater.from(context);
View v = inflater.inflate(R.layout.listitem, parent, false);
bindView(v, context, cursor);
return v;
}
可以通过在 contentResolver.query 方法中添加 where 子句(MediaStore.Audio.AudioColumns.DURATION+">0" 在我的代码中)来解决,如下所示:
cursor = getContentResolver().query(MediaStore.Audio.Media.EXTERNAL_CONTENT_URI, null,MediaStore.Audio.AudioColumns.DURATION+">0", null, sortOrder);