如何通过按钮关闭 Kivy 弹出窗口？

Question

我有一个使用 Kivy 创建的弹出窗口，其中包含 2 个按钮。用户可以通过在弹出区域外按下 (auto_dismiss = True) 或单击 "No" 按钮来关闭弹出窗口。选择 "Yes" 按钮，将退出整个应用程序。

请看相关代码：

class ExitApp(App):

def exit_confirmation(self):

    # popup can only have one Widget.  This can be fixed by adding a BoxLayout

    self.box_popup = BoxLayout(orientation = 'horizontal')

    self.box_popup.add_widget(Label(text = "Really exit?"))

    self.box_popup.add_widget(Button(
        text = "Yes",
        on_press = ExitApp.exit,
        size_hint = (0.215, 0.075)))

    self.box_popup.add_widget(Button(
        text = "No",
        on_press = self.popup_exit.dismiss,
        size_hint=(0.215, 0.075)))

    self.popup_exit = Popup(title = "Exit",
        content = self.box_popup,
        size_hint = (0.4, 0.4),
        auto_dismiss = True)

    self.popup_exit.open()

def exit(self):

    App.get_running_app().stop()

现在的问题在于按下 "No" 按钮。按下时，代码退出并出现此错误：

 on_press = self.popup_exit.dismiss,
AttributeError: 'Button' object has no attribute 'popup_exit'

知道如何尽可能轻松地解决这个问题吗？

Answer 1

试试这个：用 on_press = self.popup.dismiss() 代替 on_press = self.popup_exit.dismiss

Answer 2

将on_press = self.popup_exit.dismiss改为on_press = lambda: self.popup_exit.dismiss()，因为dismiss是一个函数，需要在按下按钮时调用。

def exit_confirmation(self):


    # popup can only have one Widget.  This can be fixed by adding a BoxLayout

    self.box_popup = BoxLayout(orientation = 'horizontal')

    self.box_popup.add_widget(Label(text = "Really exit?"))

    self.box_popup.add_widget(Button(
        text = "Yes",
        on_press = ExitApp.exit,
        size_hint = (0.215, 0.075)))

    self.popup_exit = Popup(title = "Exit",
        content = self.box_popup,
        size_hint = (0.4, 0.4),
        auto_dismiss = True)

    self.box_popup.add_widget(Button(
    text = "No",
    on_press = lambda: self.popup_exit.dismiss() ,
    size_hint=(0.215, 0.075)))

    self.popup_exit.open()

Answer 3

你可以通过惰性函数解决这个问题

on_press = lambda *args: self.popup_exit.dismiss()

这样，当按下按钮并且 popup_exit 已经到位时，仅会进行查找。 .

Answer 4

这样的东西在 kivy 中行得通吗？

on_press : root.dismiss()

Answer 5

#我发现通过按钮关闭 Kivy pop-up 的最佳方法是定义全局

#Kivy         v2.0.0
from kivy.app import App
from kivy.lang import Builder
from kivy.uix.floatlayout import FloatLayout
from kivy.uix.screenmanager import ScreenManager, Screen
from kivy.uix.popup import Popup



class GetPopUpFunctions(FloatLayout):

    def yes_click(self):
        print("banana")


    def no_click(self):
        print("closing the popup")
        self.close_popup()

    def close_popup(self):
        admin_popup.dismiss()





class AdminScreen(Screen):
    """
    Description:
    Owner:Yaki Hakimi

    """

    def open_popup(self):

        popup_functions = GetPopUpFunctions() # Create a new instance of the pop class
        global admin_popup
        admin_popup = Popup(title="Magnets", content=popup_functions, size_hint=(None,None),size=(400,400))
        admin_popup.open()


GUI = Builder.load_string("""


GridLayout:
    cols: 1
    ScreenManager:
        id: screen_manager


        AdminScreen:#name of the class
            name: "admin_screen"
            id: admin_screen


<AdminScreen>:

    GridLayout:
        cols:1
        size: root.width,  root.height

        Button:
            text : "popup debug"
            on_press :
                root.open_popup()

##############################################################
<GetPopUpFunctions>:

    Label:
        text:"popup message"
        size_hint: 0.6, 0.2
        pos_hint: {"x":0.2, "top":1}

    Button:
        text: "Yes"
        size_hint: 0.2, 0.2
        pos_hint: {"x":0.45, "y":0.4}
        on_release:
            root.yes_click()


    Button:
        text: "No"
        size_hint: 0.2, 0.2
        pos_hint: {"x":0.45, "y":0.1}
        on_release:
            root.no_click()




""")


class PopupOpenClose(App):


    def build(self):
        return GUI


if __name__ == '__main__':
    PopupOpenClose().run()

如何通过按钮关闭 Kivy 弹出窗口？

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