重复加入问题 values/rows

Question

python 的新手，似乎无法理解如何进行。在使用 bin 并编辑我的数据框后，我能够想出这个：

    Continents  % Renewable Country
0   Asia    (15.753, 29.227]    China
1   North America   (2.212, 15.753] United States
2   Asia    (2.212, 15.753] Japan
3   Europe  (2.212, 15.753] United Kingdom
4   Europe  (15.753, 29.227]    Russian Federation
5   North America   (56.174, 69.648]    Canada
6   Europe  (15.753, 29.227]    Germany
7   Asia    (2.212, 15.753] India
8   Europe  (15.753, 29.227]    France
9   Asia    (2.212, 15.753] South Korea
10  Europe  (29.227, 42.701]    Italy
11  Europe  (29.227, 42.701]    Spain
12  Asia    (2.212, 15.753] Iran
13  Australia   (2.212, 15.753] Australia
14  South America   (56.174, 69.648]    Brazil

现在，当我使用 :

将大陆和可再生能源百分比设置为 miltiindex 时

Top15 = Top15.groupby(by=['Continents', '% Renewable']).sum()

获得以下内容：

                            Country
Continents  % Renewable   
Asia    (15.753, 29.227]    China
         (2.212, 15.753]    JapanIndiaSouth KoreaIran
Australia   (2.212, 15.753] Australia
Europe  (15.753, 29.227]    Russian FederationGermanyFrance
        (2.212, 15.753] United Kingdom
        (29.227, 42.701]    ItalySpain
North America   (2.212, 15.753] United States
                 (56.174, 69.648]   Canada
South America   (56.174, 69.648]    Brazil

现在我想有一个列可以给我每个索引中的国家/地区数量，即：

第一排 - 中国 =1 ,

第二行日本印度韩国伊朗是 4

所以最后我想要这样的东西:

Asia           (2.212, 15.753]     4
               (15.753, 29.227]    1

我就是不知道怎么去。

此外，数字需要按降序排序，同时仍保持索引分组不变。

Answer 1

Top15.groupby(['Continents', '% Renewable']).Country.count()

Continents     % Renewable     
Asia           (15.753, 29.227]    1
               (2.212, 15.753]     4
Australia      (2.212, 15.753]     1
Europe         (15.753, 29.227]    3
               (2.212, 15.753]     1
               (29.227, 42.701]    2
North America  (2.212, 15.753]     1
               (56.174, 69.648]    1
South America  (56.174, 69.648]    1
Name: Country, dtype: int64

按您喜欢的顺序排序

Top15_count = Top15.groupby(['Continents', '% Renewable']).Country.count()

Top15_count.reset_index() \
    .sort_values(
        ['Continents', 'Country'],
        ascending=[True, False]
    ).set_index(['Continents', '% Renewable']).Country

Continents     % Renewable     
Asia           (2.212, 15.753]     4
               (15.753, 29.227]    1
Australia      (2.212, 15.753]     1
Europe         (15.753, 29.227]    3
               (29.227, 42.701]    2
               (2.212, 15.753]     1
North America  (2.212, 15.753]     1
               (56.174, 69.648]    1
South America  (56.174, 69.648]    1
Name: Country, dtype: int64

Answer 2

size 的解决方案：

print (Top15.groupby(['Continents', '% Renewable']).size())
Name: Country, dtype: int64
Continents     % Renewable     
Asia           (15.753, 29.227]    1
               (2.212, 15.753]     4
Australia      (2.212, 15.753]     1
Europe         (15.753, 29.227]    3
               (2.212, 15.753]     1
               (29.227, 42.701]    2
North America  (2.212, 15.753]     1
               (56.174, 69.648]    1
South America  (56.174, 69.648]    1
dtype: int64

使用sort_values if need change order and for dataframe add reset_index, last if need MultiIndex add set_index:

print (Top15.groupby(['Continents', '% Renewable']) \
            .size() \
            .reset_index(name='COUNT') \
            .sort_values(['Continents', 'COUNT'], ascending=[True, False]) \
            .set_index(['Continents','% Renewable']).COUNT)

Continents     % Renewable     
Asia           (2.212, 15.753]     4
               (15.753, 29.227]    1
Australia      (2.212, 15.753]     1
Europe         (15.753, 29.227]    3
               (29.227, 42.701]    2
               (2.212, 15.753]     1
North America  (2.212, 15.753]     1
               (56.174, 69.648]    1
South America  (56.174, 69.648]    1
Name: COUNT, dtype: int64

重复加入问题 values/rows

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