UITextView：在截断的文本中查找省略号的位置

Question

我有一个带有一些属性文本的 UITextView，其中设置了 textContainer.maximumNumberOfLine（在本例中为 3）。

我想在属性字符串的字符范围内找到省略号字符的索引。

例如：

原始字符串：

"Lorem ipsum dolor sit amet, consectetur adipiscing elit"

截断后显示的字符串：

Lorem ipsum dolor sit amet, consectetur...

如何确定 ... 的索引？

Answer 1

这是 NSAttributedString 的扩展函数，它可以完成这项工作。适用于单行和多行文本。

我花了大约 8 个小时才弄明白，所以我想 post 将其作为问答。

(Swift 2.2)

/**
    Returns the index of the ellipsis, if this attributed string is truncated, or NSNotFound otherwise.
*/
func truncationIndex(maximumNumberOfLines: Int, width: CGFloat) -> Int {

    //Create a dummy text container, used for measuring & laying out the text..

    let textContainer = NSTextContainer(size: CGSize(width: width, height: CGFloat.max))
    textContainer.maximumNumberOfLines = maximumNumberOfLines
    textContainer.lineBreakMode = NSLineBreakMode.ByTruncatingTail

    let layoutManager = NSLayoutManager()
    layoutManager.addTextContainer(textContainer)

    let textStorage = NSTextStorage(attributedString: self)
    textStorage.addLayoutManager(layoutManager)

    //Determine the range of all Glpyhs within the string

    var glyphRange = NSRange()
    layoutManager.glyphRangeForCharacterRange(NSMakeRange(0, self.length), actualCharacterRange: &glyphRange)

    var truncationIndex = NSNotFound

    //Iterate over each 'line fragment' (each line as it's presented, according to your `textContainer.lineBreakMode`)
    var i = 0
    layoutManager.enumerateLineFragmentsForGlyphRange(glyphRange) { (rect, usedRect, textContainer, glyphRange, stop) in
        if (i == maximumNumberOfLines - 1) {

            //We're now looking at the last visible line (the one at which text will be truncated)

            let lineFragmentTruncatedGlyphIndex = glyphRange.location
            if lineFragmentTruncatedGlyphIndex != NSNotFound {
                truncationIndex = layoutManager.truncatedGlyphRangeInLineFragmentForGlyphAtIndex(lineFragmentTruncatedGlyphIndex).location
            }
            stop.memory = true
        }
        i += 1
    }

    return truncationIndex
}

请注意，除了一些简单的案例之外，这还没有经过测试。可能存在需要一些调整的边缘情况..

Answer 2

我用 Swift 5

更新了@Tim Malseed 的解决方案

extension UILabel {

 var truncationIndex: Int? {
        guard let text = text else {
            return nil
        }
        let attributes: [NSAttributedString.Key: UIFont] = [.font: font]
        let attributedString = NSAttributedString(string: text, attributes: attributes)
        let textContainer = NSTextContainer(
            size: CGSize(width: frame.size.width,
                         height: CGFloat.greatestFiniteMagnitude)
        )
        textContainer.maximumNumberOfLines = numberOfLines
        textContainer.lineBreakMode = NSLineBreakMode.byTruncatingTail

        let layoutManager = NSLayoutManager()
        layoutManager.addTextContainer(textContainer)

        let textStorage = NSTextStorage(attributedString: attributedString)
        textStorage.addLayoutManager(layoutManager)

        //Determine the range of all Glpyhs within the string
        var glyphRange = NSRange()
        layoutManager.glyphRange(
            forCharacterRange: NSMakeRange(0, attributedString.length),
            actualCharacterRange: &glyphRange
        )

        var truncationIndex = NSNotFound
        //Iterate over each 'line fragment' (each line as it's presented, according to your `textContainer.lineBreakMode`)
        var i = 0
        layoutManager.enumerateLineFragments(
            forGlyphRange: glyphRange
        ) { rect, usedRect, textContainer, glyphRange, stop in
            if (i == self.numberOfLines - 1) {
                //We're now looking at the last visible line (the one at which text will be truncated)
                let lineFragmentTruncatedGlyphIndex = glyphRange.location
                if lineFragmentTruncatedGlyphIndex != NSNotFound {
                    truncationIndex = layoutManager.truncatedGlyphRange(inLineFragmentForGlyphAt: lineFragmentTruncatedGlyphIndex).location
                }
                stop.pointee = true
            }
            i += 1
        }
        return truncationIndex
    }
}