无法为我的 iOS VoIP 应用程序显示 onComingCall ViewController

Question

我希望我的应用程序在收到一些来电时显示 IncomingCall ViewController。

这是我用来显示来电的代码。来自我的联系人ViewController，当来电发生时，它是活动视图。

- (void)showIncomigCallVC{
    [self performSegueWithIdentifier:@"segueToIncomingCallVC" sender:nil];
}

这是我的代码，由图书馆调用。

    /* Callback called by the library upon receiving incoming call */
static void on_incoming_call(pjsua_acc_id acc_id, pjsua_call_id call_id,
                         pjsip_rx_data *rdata)
{
    pjsua_call_info ci;

    PJ_UNUSED_ARG(acc_id);
    PJ_UNUSED_ARG(rdata);

    pjsua_call_get_info(call_id, &ci);



    PJ_LOG(3,(THIS_FILE, "....\n\n\n Incoming call from %.*s!!  \n\n\n",
          (int)ci.remote_info.slen,
          ci.remote_info.ptr));

    ContactsViewController *incomingCallVC = [[ContactsViewController alloc]init];
    [incomingCallVC showIncomigCallVC];

    /* Automatically answer incoming calls with 200/OK */
    pjsua_call_answer(call_id, 200, NULL, NULL);
}

这是我的控制台输出：

20:39:37.482      XCPjsua.c  ......


Incoming call from <sip:eeshaMiss12@ekiga.net>!!  



2017-01-16 20:39:37.494 simpleVoIP[922:19652] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Receiver (<ContactsViewController: 0x7bea3d00>) has  no segue with identifier 'segueToIncomingCallVC''
*** First throw call stack:
(
    0   CoreFoundation                      0x03a14212 __exceptionPreprocess + 194
    1   libobjc.A.dylib                     0x034d3e66 objc_exception_throw + 52
    2   UIKit                               0x01a69893 -[UIViewController shouldPerformSegueWithIdentifier:sender:] + 0
    3   simpleVoIP                          0x00089ba6 -[ContactsViewController showIncomigCallVC] + 70
    4   simpleVoIP                          0x00086caf on_incoming_call + 255
    5   simpleVoIP                          0x000fc273 pjsua_call_on_incoming + 3811
    6   simpleVoIP                          0x00103294 mod_pjsua_on_rx_request + 84
    7   simpleVoIP                          0x0012938f pjsip_endpt_process_rx_data + 351
    8   simpleVoIP                          0x00128bf2 endpt_on_rx_msg + 546
    9   simpleVoIP                          0x0012fba1 pjsip_tpmgr_receive_packet + 849
    10  simpleVoIP                          0x001315ec udp_on_read_complete + 316
    11  simpleVoIP                          0x0014b8e0 ioqueue_dispatch_read_event + 704
    12  simpleVoIP                          0x0014d5b2 pj_ioqueue_poll + 946
    13  simpleVoIP                          0x001290c3 pjsip_endpt_handle_events2 + 163
    14  simpleVoIP                          0x00102023 worker_thread + 99
    15  simpleVoIP                          0x0014eb96 thread_main + 86
    16  libsystem_pthread.dylib             0x04c8a11b _pthread_body + 184
    17  libsystem_pthread.dylib             0x04c8a063 _pthread_body + 0
    18  libsystem_pthread.dylib             0x04c8993e thread_start + 34
)
libc++abi.dylib: terminating with uncaught exception of type NSException

我是初学者，如有任何建议，我们将不胜感激。提前致谢

Answer 1

您遇到了崩溃，因为您正在以编程方式分配 ContactsViewController，而不是使用 storyboard。

当你这样做时：

 ContactsViewController *incomingCallVC = [[ContactsViewController alloc]init];
 [incomingCallVC showIncomigCallVC];

您正在创建 ContactsViewController 的实例，与我们 storyboard.
中创建的实例无关有可能克服这一点，但是，您正在尝试对 viewController 进行 segue 调用，只加载到内存中，但根本不可见。那永远行不通，它总是会崩溃。

我建议立即显示您的 viewController，无论是在 segue 后面，而不是创建 viewController 并用 segue 显示它。

编辑:

使用下面的代码，您应该能够在回调函数的末尾显示您想要的 UIViewController 子类。

// Lets get keywindow 
UIWindow* keyWindow = [[[UIApplication sharedApplication] delegate] window]; 
keyWindow.frame = [UIScreen mainScreen].bounds; 

// Lets get `IncomingCallViewController` from storyboard 
UIStoryboard *sb = [UIStoryboard storyboardWithName:@"TheNameOfYourStoryboard" bundle:nil]; 
// do not forget to set the identifier of your viewController on the storyboard as "IncomingCallViewController" 
UIViewController *vc = [sb instantiateViewControllerWithIdentifier:@"IncomingCallViewController"]; 
// Lets present the keyWindow from the main thread
dispatch_async(dispatch_get_main_queue(), ^{ 
   keyWindow.rootViewController = vc; 
   [keyWindow makeKeyAndVisible]; 
});

无法为我的 iOS VoIP 应用程序显示 onComingCall ViewController

Unable to Show onComingCall ViewController for my iOS VoIP Application

objective-c

pjsip

ios