我坚持这个 DATEDIFF

Question

好吧，我一直收到这个错误：

Msg 245, Level 16, State 1, Line 1 Conversion failed when converting the varchar value ' Days ' to data type int.

下面是我的代码......我在这里做错了什么......我试图显示日期，小时和分钟的差异......我在我的datediff中使用了CASTS因为它们不同列，所以我使用 cast 将它们连接起来，以便更容易地做我的 datediff.....

DATEDIFF(DD, checkin_datetime, CAST(txt_signoff_ml_date AS DATETIME) + CAST(txt_signoff_ml_time AS DATETIME)) + ' Days ' 
        + DATEDIFF(HH, checkin_datetime, CAST(txt_signoff_ml_date AS DATETIME) + CAST(txt_signoff_ml_time AS DATETIME)) + ' Hours '
        + DATEDIFF(MINUTE, checkin_datetime, CAST(txt_signoff_ml_date AS DATETIME) + CAST(txt_signoff_ml_time AS DATETIME)) + ' Minutes'
AS Time_diff2,

Answer 1

这个：

DATEDIFF(DD, checkin_datetime, CAST(txt_signoff_ml_date AS DATETIME)

需要右括号。这应该让你开始。

Answer 2

DateDiff 函数将return 产生整数。在这里，您组合了整数值和字符串值。因此，您面临类型差异错误。

您必须将 datediff 输出转换为 varchar，如下所述

cast(DATEDIFF(DD, checkin_datetime, CAST(txt_signoff_ml_date AS DATETIME) + CAST(txt_signoff_ml_time AS DATETIME))as varchar(50)) + ' Days ' 
        + cast(DATEDIFF(HH, checkin_datetime, CAST(txt_signoff_ml_date AS DATETIME) + CAST(txt_signoff_ml_time AS DATETIME))as varchar(50)) + ' Hours '
        + cast(DATEDIFF(MINUTE, checkin_datetime, CAST(txt_signoff_ml_date AS DATETIME) + CAST(txt_signoff_ml_time AS DATETIME)) as varchar(50)) + ' Minutes'

我坚持这个 DATEDIFF

Im stuck with this DATEDIFF

tsql

sql-server

datediff