转换为 UTC 时间

Question

我正在尝试将我的数据转换为 DateTime 和 AssumeUniversal，但出现

错误

String was not recognized as a valid DateTime

这是传入的格式

1/10/2017 1:13:00 PM

这是我的跟踪事件class

public partial class TrackEvent {
    private System.DateTime timestampField;
    private bool timestampFieldSpecified;
    private string eventTypeField;
    private string eventDescriptionField;
    private string statusExceptionCodeField;
    private string statusExceptionDescriptionField;
    private Address addressField;
    private string stationIdField;
    private ArrivalLocationType arrivalLocationField;
    private bool arrivalLocationFieldSpecified;

    /// <remarks/>
    public System.DateTime Timestamp {
        get {
            return this.timestampField;
        }
        set {
            this.timestampField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlIgnoreAttribute()]
    public bool TimestampSpecified {
        get {
            return this.timestampFieldSpecified;
        }
        set {
            this.timestampFieldSpecified = value;
        }
    }

    /// <remarks/>
    public string EventType {
        get {
            return this.eventTypeField;
        }
        set {
            this.eventTypeField = value;
        }
    }

    /// <remarks/>
    public string EventDescription {
        get {
            return this.eventDescriptionField;
        }
        set {
            this.eventDescriptionField = value;
        }
    }

    /// <remarks/>
    public string StatusExceptionCode {
        get {
            return this.statusExceptionCodeField;
        }
        set {
            this.statusExceptionCodeField = value;
        }
    }

    /// <remarks/>
    public string StatusExceptionDescription {
        get {
            return this.statusExceptionDescriptionField;
        }
        set {
            this.statusExceptionDescriptionField = value;
        }
    }

    /// <remarks/>
    public Address Address {
        get {
            return this.addressField;
        }
        set {
            this.addressField = value;
        }
    }

    /// <remarks/>
    public string StationId {
        get {
            return this.stationIdField;
        }
        set {
            this.stationIdField = value;
        }
    }

    /// <remarks/>
    public ArrivalLocationType ArrivalLocation {
        get {
            return this.arrivalLocationField;
        }
        set {
            this.arrivalLocationField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlIgnoreAttribute()]
    public bool ArrivalLocationSpecified {
        get {
            return this.arrivalLocationFieldSpecified;
        }
        set {
            this.arrivalLocationFieldSpecified = value;
        }
    }
}

这就是我尝试调用转换的方式：

TrackEvent currMax = new TrackEvent();
currMax.Timestamp = DateTime.MinValue;
foreach (TrackEvent trackevent in trackDetail.Events)
{  
 if (trackevent.TimestampSpecified && trackevent.Timestamp > currMax.Timestamp)
{
  currMax = trackevent;                 
  var formats = new[]
  {
    "MM/dd/yyyy hh:mm tt",
    "MM/dd/yyyy hh:mmtt",
    "MM/dd/yyyy h:mm tt",
    "MM/dd/yyyy h:mmtt",
    "MM/dd/yyyy hhtt",
    "MM/dd/yyyy htt",
    "MM/dd/yyyy h tt",
    "MM/dd/yyyy hh tt",
    "MM/dd/yyyy HH:mm:ss.fff",
    "MM/dd/yyyy h:mm:ss tt"
  };
    DateTime time = DateTime.ParseExact(currMax.Timestamp.ToString(), formats, System.Globalization.CultureInfo.InvariantCulture, 
    System.Globalization.DateTimeStyles.AssumeUniversal |      System.Globalization.DateTimeStyles.AdjustToUniversal);
    Console.WriteLine(time);
  }
}

Answer 1

您使用 DateTime.ParseExact，它将查看您所有给定的格式，将 string 解析为 DateTime。

但是输入datetime格式

1/10/2017 1:13:00 PM

的月份只有一个数字（即 M/dd ...），而你所有 formats 解析输入 datetimewith DateTime.ParseExact 仅支持两个数字 day/month （即：MM/dd ...）：

  var formats = new[]
  {
    "MM/dd/yyyy hh:mm tt",
    "MM/dd/yyyy hh:mmtt",
    "MM/dd/yyyy h:mm tt",
    "MM/dd/yyyy h:mmtt",
    "MM/dd/yyyy hhtt",
    "MM/dd/yyyy htt",
    "MM/dd/yyyy h tt",
    "MM/dd/yyyy hh tt",
    "MM/dd/yyyy HH:mm:ss.fff",
    "MM/dd/yyyy h:mm:ss tt"
  };

请注意，您在所有格式中都使用 MM/dd ...

要更正它，您还应该在 formats 中包含允许单个数字作为 day/month 表示的格式：

   var formats = new[]
  {
    "M/d/yyyy hh:mm tt",
    "M/d/yyyy hh:mmtt",
    "M/d/yyyy h:mm tt",
    "M/d/yyyy h:mmtt",
    "M/d/yyyy hhtt",
    "M/d/yyyy htt",
    "M/d/yyyy h tt",
    "M/d/yyyy hh tt",
    "M/d/yyyy HH:mm:ss.fff",
    "M/d/yyyy h:mm:ss tt"
  };

以上格式将同时支持个位数和双位数日期和月份

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