Android 如何在 AsyncTask 中保存变量
How to save a variable in AsyncTask in Android
我正在使用 Twitter 4j post 在单个按钮上发推文。如果用户撤销对我的应用程序的访问权限,那么它会在后台显示 Logcat 错误,我想要这个错误,如果这个错误出现,我的 Twitter 授权应用程序的另一个隐藏按钮可见。我该怎么做,请帮忙。我需要那个错误,如果它存在我想隐藏显示我的按钮。
class updateTwitterStatus extends AsyncTask<String, String, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
}
protected Void doInBackground(String... args) {
String status = args[0];
try {
ConfigurationBuilder builder = new ConfigurationBuilder();
builder.setOAuthConsumerKey(consumerKey);
builder.setOAuthConsumerSecret(consumerSecret);
String access_token = mSharedPreferences.getString(PREF_KEY_OAUTH_TOKEN, "");
String access_token_secret = mSharedPreferences.getString(PREF_KEY_OAUTH_SECRET, "");
AccessToken accessToken = new AccessToken(access_token, access_token_secret);
twitter4j.Twitter twitter = new TwitterFactory(builder.build()).getInstance(accessToken);
StatusUpdate statusUpdate = new StatusUpdate(status);
File extStore = Environment.getExternalStoragePublicDirectory("/Twitter/Cache/demo.jpg");
statusUpdate.setMedia(extStore);
twitter4j.Status response = twitter.updateStatus(statusUpdate);
} catch (TwitterException e) {
Log.d("Failed to post!", e.getMessage());
error=e; //error is exception
}
return null;}
@Override
protected void onPostExecute(Void result) {
pDialog.dismiss();
Toast.makeText(getContext(), "Posted to Twitter!"+error, Toast.LENGTH_SHORT).show();
/* i need a variable like int a =10; access it globally, How i do that/*
} } }
您可以将 exception
保存在变量中并在 onPostExecute
() 中检查它
并隐藏你的按钮..
new AsyncTask<Void, Void, Boolean>() {
Exception error;
@Override
protected Boolean doInBackground(Void... params) {
try {
// do work
return true;
} catch (Exception e) {
error = e;
return false;
}
}
@Override
protected void onPostExecute(Boolean result) {
if (result) {
Toast.makeText(ctx, "Success!",
Toast.LENGTH_SHORT).show();
} else {
if (error != null) {
Toast.makeText(getApplicationContext(), error.getMessage(),
Toast.LENGTH_SHORT).show();
//error occurs hide button here
}
}
}
}
我正在使用 Twitter 4j post 在单个按钮上发推文。如果用户撤销对我的应用程序的访问权限,那么它会在后台显示 Logcat 错误,我想要这个错误,如果这个错误出现,我的 Twitter 授权应用程序的另一个隐藏按钮可见。我该怎么做,请帮忙。我需要那个错误,如果它存在我想隐藏显示我的按钮。
class updateTwitterStatus extends AsyncTask<String, String, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
}
protected Void doInBackground(String... args) {
String status = args[0];
try {
ConfigurationBuilder builder = new ConfigurationBuilder();
builder.setOAuthConsumerKey(consumerKey);
builder.setOAuthConsumerSecret(consumerSecret);
String access_token = mSharedPreferences.getString(PREF_KEY_OAUTH_TOKEN, "");
String access_token_secret = mSharedPreferences.getString(PREF_KEY_OAUTH_SECRET, "");
AccessToken accessToken = new AccessToken(access_token, access_token_secret);
twitter4j.Twitter twitter = new TwitterFactory(builder.build()).getInstance(accessToken);
StatusUpdate statusUpdate = new StatusUpdate(status);
File extStore = Environment.getExternalStoragePublicDirectory("/Twitter/Cache/demo.jpg");
statusUpdate.setMedia(extStore);
twitter4j.Status response = twitter.updateStatus(statusUpdate);
} catch (TwitterException e) {
Log.d("Failed to post!", e.getMessage());
error=e; //error is exception
}
return null;}
@Override
protected void onPostExecute(Void result) {
pDialog.dismiss();
Toast.makeText(getContext(), "Posted to Twitter!"+error, Toast.LENGTH_SHORT).show();
/* i need a variable like int a =10; access it globally, How i do that/*
} } }
您可以将 exception
保存在变量中并在 onPostExecute
() 中检查它
并隐藏你的按钮..
new AsyncTask<Void, Void, Boolean>() {
Exception error;
@Override
protected Boolean doInBackground(Void... params) {
try {
// do work
return true;
} catch (Exception e) {
error = e;
return false;
}
}
@Override
protected void onPostExecute(Boolean result) {
if (result) {
Toast.makeText(ctx, "Success!",
Toast.LENGTH_SHORT).show();
} else {
if (error != null) {
Toast.makeText(getApplicationContext(), error.getMessage(),
Toast.LENGTH_SHORT).show();
//error occurs hide button here
}
}
}
}