如何将字符添加到二维数组？

Question

我的代码：

FILE * file;

file = fopen("c://catalog//file.txt", "r");
int m,n; //size of 2d array (m x n)
fscanf(file, "%d", &m);
fscanf(file, "%d", &n);
fclose(file);

printf("Size: %d x %d\n", m, n);

// create 2d array 
char **TAB2 = new char*[m];
for (int i = 0; i < m; i++)
    char *TAB2 = new char[n];

// display 2d array 
for (int i = 0; i < m; i++){
    for (int j = 0; j < n; j++)
    {
        printf("%c ", &TAB2[i][j]);
    }
    printf("\n");
}

如何用字符或字符串填充这个数组？例如文本 = "someting"，对于数组 3x5 将是：

S o m e t
h i n g ?
? ? ? ? ?

我试过了：TAB2[0][0] = 's'； *&TAB2[0][0] = 's';对于一个字符，这不起作用...

可能是我用不好指针（？）。有人帮帮我吗？

Answer 1

动态分配数组错误

char **TAB2 = new char*[m];
for (int i = 0; i < m; ++i)
    TAB2[i] = new char[n];

检查这个 link 寻求帮助。

你可以试试这个：

#include<iostream>
using namespace std;

int main() {

  const int m = 3, n = 5;
  char **TAB2 = new char*[m];
  for (int i = 0; i < m; ++i)
      TAB2[i] = new char[n];

  char c;
  for (int i = 0; i < m; ++i) {
    for (int j = 0; j < n; ++j) {
      std::cin >> c;
      TAB2[i][j] = c;
    }
  }

  for (int i = 0; i < m; ++i) {
    for (int j = 0; j < n; ++j) {
      std::cout << TAB2[i][j];
    }
    std::cout << "\n";
  }

  // NEVER FORGET TO FREE YOUR DYNAMIC MEMORY
  for(int i = 0; i < m; ++i)
    delete [] TAB2[i];
  delete [] TAB2;

  return 0;
}

输出：

jorje
georg
klouv
jorje
georg
klouv

重要链接：

How do I declare a 2d array in C++ using new?
How do I use arrays in C++?

Answer 2

数组的分配似乎不正确；应该是这样的。

char **TAB2 = new char*[m];
for (int i = 0; i < m; i++)
    TAB2[i] = new char[n];

如何将字符添加到二维数组？

How to add chars to 2D array?

c++

arrays

pointers

multidimensional-array