没有 UNPIVOT 的 Oracle SQL 列到行
Oracle SQL Columns to Rows without UNPIVOT
我目前拥有的:
Team User Apples Oranges Pears
Red Adam 4 5 6
Red Avril 11 12 13
Blue David 21 22 23
需要什么:
Team User Product Count
Red Adam Apples 4
Red Adam Oranges 5
Red Adam Pears 6
Red Avril Apples 11
Red Avril Oranges 12
Red Avril Pears 13
Blue David Apples 21
....
这将使用 Oracle SQL 来实现。我知道这可以使用 UNPIVOT 来完成,但是我的 Oracle SQL 版本太旧,不支持这种方法。有人可以举例说明如何使用 CROSS APPLY 或等效方法实现此目的吗? 数量 根据团队-用户-产品组合而变化,并且产品类型的数量将来可能会略有变化,因此可能需要可扩展的解决方案。
这是时效性的,非常感谢您的帮助。
你可以像这样使用一个大联合:
select
Team,
"User",
'Apples' Product,
Apples "Count"
from your_table
union all
select
Team,
"User",
'Oranges' Product,
Oranges "Count"
from your_table
union all
select
Team,
"User",
'Pears' Product,
Pears "Count"
from your_table
union all
. . .
此外,尽量不要使用 User 或 Count 等关键字作为标识符,否则,请像我一样将它们用双引号引起来.
您可以使用交叉连接和一些 case 语句来执行此操作,方法是使用一个虚拟子查询,该子查询包含与您想要逆透视的列相同的行数(因为您希望每一列都进入其自己的行) 像这样:
WITH your_table AS (SELECT 'Red' Team, 'Adam' usr, 4 Apples, 5 Oranges, 6 Pears FROM dual UNION ALL
SELECT 'Red' Team, 'Avril' usr, 11 Apples, 12 Oranges, 13 Pears FROM dual UNION ALL
SELECT 'Blue' Team, 'David' usr, 21 Apples, 22 Oranges, 23 Pears FROM dual)
-- end of mimicking your table. See SQL below:
SELECT yt.team,
yt.usr,
CASE WHEN d.id = 1 THEN 'Apples'
WHEN d.id = 2 THEN 'Oranges'
WHEN d.id = 3 THEN 'Pears'
END product,
CASE WHEN d.id = 1 THEN yt.apples
WHEN d.id = 2 THEN yt.oranges
WHEN d.id = 3 THEN yt.pears
END count_of_product
FROM your_table yt
CROSS JOIN (SELECT LEVEL ID
FROM dual
CONNECT BY LEVEL <= 3) d -- number of columns to unpivot
ORDER BY team, usr, product;
TEAM USR PRODUCT COUNT_OF_PRODUCT
---- ----- ------- ----------------
Blue David Apples 21
Blue David Oranges 22
Blue David Pears 23
Red Adam Apples 4
Red Adam Oranges 5
Red Adam Pears 6
Red Avril Apples 11
Red Avril Oranges 12
Red Avril Pears 13
这样做意味着您只需通过 table 一次,而不是如果您使用 union all 方法需要多次。
ETA:这是 Aleksej 所指的方法 - 我建议针对您的数据集(希望数据足够大以具有代表性)测试这两种方法,以查看哪种方法性能更高:
WITH your_table AS (SELECT 'Red' Team, 'Adam' usr, 4 Apples, 5 Oranges, 6 Pears FROM dual UNION ALL
SELECT 'Red' Team, 'Avril' usr, 11 Apples, 12 Oranges, 13 Pears FROM dual UNION ALL
SELECT 'Blue' Team, 'David' usr, 21 Apples, 22 Oranges, 23 Pears FROM dual)
-- end of mimicking your table. See SQL below:
SELECT yt.team,
yt.usr,
CASE WHEN LEVEL = 1 THEN 'Apples'
WHEN LEVEL = 2 THEN 'Oranges'
WHEN LEVEL = 3 THEN 'Pears'
END product,
CASE WHEN LEVEL = 1 THEN yt.apples
WHEN LEVEL = 2 THEN yt.oranges
WHEN LEVEL = 3 THEN yt.pears
END count_of_product
FROM your_table yt
CONNECT BY PRIOR team = team
AND PRIOR usr = usr
AND PRIOR sys_guid() IS NOT NULL
AND LEVEL <= 3
ORDER BY team, usr, product;
TEAM USR PRODUCT COUNT_OF_PRODUCT
---- ----- ------- ----------------
Blue David Apples 21
Blue David Oranges 22
Blue David Pears 23
Red Adam Apples 4
Red Adam Oranges 5
Red Adam Pears 6
Red Avril Apples 11
Red Avril Oranges 12
Red Avril Pears 13
我目前拥有的:
Team User Apples Oranges Pears
Red Adam 4 5 6
Red Avril 11 12 13
Blue David 21 22 23
需要什么:
Team User Product Count
Red Adam Apples 4
Red Adam Oranges 5
Red Adam Pears 6
Red Avril Apples 11
Red Avril Oranges 12
Red Avril Pears 13
Blue David Apples 21
....
这将使用 Oracle SQL 来实现。我知道这可以使用 UNPIVOT 来完成,但是我的 Oracle SQL 版本太旧,不支持这种方法。有人可以举例说明如何使用 CROSS APPLY 或等效方法实现此目的吗? 数量 根据团队-用户-产品组合而变化,并且产品类型的数量将来可能会略有变化,因此可能需要可扩展的解决方案。
这是时效性的,非常感谢您的帮助。
你可以像这样使用一个大联合:
select
Team,
"User",
'Apples' Product,
Apples "Count"
from your_table
union all
select
Team,
"User",
'Oranges' Product,
Oranges "Count"
from your_table
union all
select
Team,
"User",
'Pears' Product,
Pears "Count"
from your_table
union all
. . .
此外,尽量不要使用 User 或 Count 等关键字作为标识符,否则,请像我一样将它们用双引号引起来.
您可以使用交叉连接和一些 case 语句来执行此操作,方法是使用一个虚拟子查询,该子查询包含与您想要逆透视的列相同的行数(因为您希望每一列都进入其自己的行) 像这样:
WITH your_table AS (SELECT 'Red' Team, 'Adam' usr, 4 Apples, 5 Oranges, 6 Pears FROM dual UNION ALL
SELECT 'Red' Team, 'Avril' usr, 11 Apples, 12 Oranges, 13 Pears FROM dual UNION ALL
SELECT 'Blue' Team, 'David' usr, 21 Apples, 22 Oranges, 23 Pears FROM dual)
-- end of mimicking your table. See SQL below:
SELECT yt.team,
yt.usr,
CASE WHEN d.id = 1 THEN 'Apples'
WHEN d.id = 2 THEN 'Oranges'
WHEN d.id = 3 THEN 'Pears'
END product,
CASE WHEN d.id = 1 THEN yt.apples
WHEN d.id = 2 THEN yt.oranges
WHEN d.id = 3 THEN yt.pears
END count_of_product
FROM your_table yt
CROSS JOIN (SELECT LEVEL ID
FROM dual
CONNECT BY LEVEL <= 3) d -- number of columns to unpivot
ORDER BY team, usr, product;
TEAM USR PRODUCT COUNT_OF_PRODUCT
---- ----- ------- ----------------
Blue David Apples 21
Blue David Oranges 22
Blue David Pears 23
Red Adam Apples 4
Red Adam Oranges 5
Red Adam Pears 6
Red Avril Apples 11
Red Avril Oranges 12
Red Avril Pears 13
这样做意味着您只需通过 table 一次,而不是如果您使用 union all 方法需要多次。
ETA:这是 Aleksej 所指的方法 - 我建议针对您的数据集(希望数据足够大以具有代表性)测试这两种方法,以查看哪种方法性能更高:
WITH your_table AS (SELECT 'Red' Team, 'Adam' usr, 4 Apples, 5 Oranges, 6 Pears FROM dual UNION ALL
SELECT 'Red' Team, 'Avril' usr, 11 Apples, 12 Oranges, 13 Pears FROM dual UNION ALL
SELECT 'Blue' Team, 'David' usr, 21 Apples, 22 Oranges, 23 Pears FROM dual)
-- end of mimicking your table. See SQL below:
SELECT yt.team,
yt.usr,
CASE WHEN LEVEL = 1 THEN 'Apples'
WHEN LEVEL = 2 THEN 'Oranges'
WHEN LEVEL = 3 THEN 'Pears'
END product,
CASE WHEN LEVEL = 1 THEN yt.apples
WHEN LEVEL = 2 THEN yt.oranges
WHEN LEVEL = 3 THEN yt.pears
END count_of_product
FROM your_table yt
CONNECT BY PRIOR team = team
AND PRIOR usr = usr
AND PRIOR sys_guid() IS NOT NULL
AND LEVEL <= 3
ORDER BY team, usr, product;
TEAM USR PRODUCT COUNT_OF_PRODUCT
---- ----- ------- ----------------
Blue David Apples 21
Blue David Oranges 22
Blue David Pears 23
Red Adam Apples 4
Red Adam Oranges 5
Red Adam Pears 6
Red Avril Apples 11
Red Avril Oranges 12
Red Avril Pears 13